剑指offer——合并两个有序的链表

 1 /*
 2 public class ListNode {
 3     int val;
 4     ListNode next = null;
 5 
 6     ListNode(int val) {
 7         this.val = val;
 8     }
 9 }*/
10 public class Solution {
11     public ListNode Merge(ListNode l1,ListNode l2) {
12         if(l1==null)
13             return l2;
14         if(l2==null)
15             return l1;
16         
17         ListNode head = new ListNode(-1);
18         ListNode merge = head;
19         
20         while(l1!=null&&l2!=null)
21         {
22             if(l1.val<l2.val)
23             {
24                 merge.next =l1;
25                 merge = merge.next;
26                 l1 = l1.next;
27             }
28             else
29             {
30                 merge.next = l2;
31                 merge = merge.next;
32                 l2 = l2.next;
33             }
34         }
35         if(l1!=null)
36         {
37             merge.next = l1;
38         }
39         if(l2!=null)
40         {
41             merge.next = l2;
42         }
43         return head.next;
44         
45     }
46 }

 

posted @ 2019-06-23 19:09  王爷爱吃秋刀鱼  阅读(149)  评论(0编辑  收藏  举报