c++ 正则表达式 

 1     vector<CString> vVector;
 2     smatch result;
 3     string strResult = "";
 4 
 5     regex pattern("(O\\d{4})((.*\\r\\n)*?)(M99)");
 6     string strMatch = strFile;
 7     string::const_iterator iterStart = strMatch.begin();
 8     string::const_iterator iterEnd = strMatch.end();
 9     //搜索G00，并找到程序头中最后一个G00的位置
10     while (regex_search(iterStart, iterEnd, result, pattern))
11     {
12         strResult = result[0];
13         iterStart = result[0].second;
14         CString strTemp(strResult.c_str());
15         vVector.push_back(strTemp);
16     }

 

posted on 2021-04-02 13:43  望月又一  阅读(111)  评论(0)  编辑  收藏  举报