摘要： 1 //no.1 leap():if leap:return=1;else:return=0; 2 //no.2 sum_day(oy,om,od,ny,nm,nd):return=s; 3 //no.3 sum_second(int h,int m,long s):return=s; 4 //no.4 delay(int n):no return 5 //no.5 countdown... 阅读全文