Python-基础算法之二维数组90度旋转

 

Python-基础算法之二维数组90度旋转

http://www.cnblogs.com/alex3714/articles/5143440.html

要求：生成一个4*4的2维数组并将其顺时针旋转90度

>>> a = []
>>> for i in range(10):
...     a.append(i)
... 
>>> print(a)
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> b = [ i for i in range(10)]
>>> b
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>>


>>> a = [[col for col in  range(4)] for raw in  range(4)]
>>> a
[[0, 1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3]]
>>> for i in a:
...     print(i)
... 
[0, 1, 2, 3]
[0, 1, 2, 3]
[0, 1, 2, 3]
[0, 1, 2, 3]
>>>





data = [[col for col in  range(4)] for row in  range(4)]
for row in data:
    print(row)
print('--------------')

for i in range(len(data)):
    #print(i)
    a = [data[i][i] for row in range(4)]
    print(a)

/Library/Frameworks/Python.framework/Versions/3.6/bin/python3.6 /Users/admin/PycharmProjects/s18/day3/二分法.py
[0, 1, 2, 3]
[0, 1, 2, 3]
[0, 1, 2, 3]
[0, 1, 2, 3]
--------------
[0, 0, 0, 0]
[1, 1, 1, 1]
[2, 2, 2, 2]
[3, 3, 3, 3]


http://www.jb51.net/article/53051.htm


a = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
# c = [ [row[col] for row in a] for col in range(len(a[0]))]
# print(c)
for col in range(len(a)):
    b = []
    c = []
    for row in range(len(a)):
        c.append(a[row][col])
    b.append(c)
    print(b)

/Library/Frameworks/Python.framework/Versions/3.6/bin/python3.6 /Users/admin/PycharmProjects/s18/day3/二分法.py
[[1, 4, 7]]
[[2, 5, 8]]
[[3, 6, 9]]