python实现买啤酒（2元一瓶，4个瓶盖换一瓶，2个瓶子换一瓶）

题目：啤酒2元一瓶，4个瓶盖换一瓶，2个瓶子换一瓶，问10元钱能喝几瓶？

把生活中的事情转换成代码，我们首先要做的是找出事情的规律：

　　喝酒产生瓶盖和瓶子，瓶盖和瓶子又能换酒，酒又产生瓶盖和瓶子，如此不断循环，那么就很容易让人想到递归。只要对细节稍加控制，就可以完成计算了。

代码如下：

#!/usr/bin/env python3
# -*- coding:utf-8 -*-
count = 0
surplus_bottleTop = 0
surplus_bottle = 0
def drinkAndSurplus(bottleTop, bottle):
    global count,surplus_bottleTop,surplus_bottle
    beers = 0
    beers += bottleTop//4
    beers += bottle//2
    count += beers
    bottleTop = bottleTop%4 + beers
    bottle = bottle%2 + beers
    print('本次喝了%d瓶，剩余瓶盖%d个，剩余瓶子%d个'%(beers, bottleTop, bottle))
    if(bottleTop//4 > 0 or bottle//2 > 0):
        drinkAndSurplus(bottleTop, bottle)
    else:
        surplus_bottleTop = bottleTop
        surplus_bottle = bottle
if __name__ == '__main__':
    money = 10
    count, surplus_bottleTop, surplus_bottle = money//2, money//2, money//2
    print('总共%d元钱,本次喝酒%d瓶，剩余瓶盖%d个，剩余瓶子%d个'%(money,count,count,count))
    drinkAndSurplus(surplus_bottleTop, surplus_bottle)
    print('总共喝了%d瓶，剩余瓶盖%d个，剩余瓶子%d个'%(count,surplus_bottleTop,surplus_bottle))

 

执行结果如下：

python新手，大神勿喷！