【错题集】python基础之字符串的格式化循环语句与注释

多选题　下面格式化字符串的代码，哪些是错误的（5.00分）

　　　　A: 'my name is %s'.format('Mike')
　　　　B:'my name is {}{}'.format('Mike')

　　　　C:"my name is {}, I'm {} years old.".format('Mike',5)

　　　　D:"my name is {}, I'm {} years old.".format(['Mike',5])

　　　　答案：A D

　　　　标准答案：

判断题　格式化字符串'%9.2f'表示参数数字的小数部分保留2位， 同时还指明了最小宽度是9，不足补空格。  (5.00分)

　　　　正确

　　　　错误

　　　　答案：正确

　　　　标准答案：

编程题1、　

请实现一个程序，实现如下需求点：

1.程序开始的时候提示用户输入学生年龄信息 格式如下：

Jack Green , 21 ; Mike Mos, 9;

我们假设 用户输入 上面的信息，必定会遵守下面的规则：
学生信息之间用分号隔开（分号前后可能有不定数量的空格），
每个学生信息里的 姓名和 年龄之间用 逗号隔开（逗号前后可能有不定数量的空格）

2. 程序随后将输入的学生信息分行显示，格式如下
Jack Green : 21;
Mike Mos : 09;
学生的姓名要求左对齐，宽度为20， 年龄信息右对齐，宽度为2位，不足前面补零

自己答案：

N1 = input('请输出对应的内容：')
# N1 = 'Jack Green ,   21  ;  Mike Mos, 9;Mike kill,      54513;'
N2 = N1.split(';')
del N2[-1]#删除元组末尾的“；”
for i in  range(len(N2)):
    # print(N2[i].split(','))
    name = N2[i].split(',')[0].strip()
    age = N2[i].split(',')[1].strip()
    print('{:<20}{:0>10}'.format(name, age))

参考答案：

inputStr = input('Please input student age info:')
studentInfo = inputStr.split(';')
for one in studentInfo:
# check if it is valid input
if ',' not in one:
continue
name,age = one.split(',')
name = name.strip()
age = age.strip()
# check is age digit
if not age.isdigit():
continue
age = int(age)

print('%-20s : %02d' % (name, age))
# print('{:20} : {:02}'.format(name, age))
# print(f'{name:20} : {age:02}')

总结：

 

编程题2、

1.下面的log变量记录了云服务器上 当天上传的文件信息
其中第一列是文件名，第二列是文件大小

请编写一个程序，统计出不同类型的 文件的大小总和
比如：
jpeg 9988999
json 324324
png 2423233

log = '''
f20180111014341/i_51a7hC3W.jpeg 169472 FrITJxleSP7wUD-MWw-phL_KP6Eu 15156063244230469 image/jpeg 0
f20180111014341/j_R0Hpl4EG.json 1036 ForGzwzV3e-uR3_UzvppJs1VgfQG 15156064773253144 application/json 0
f20180111020739/i_0TDKs0rD.jpeg 169472 FrITJxleSP7wUD-MWw-phL_KP6Eu 15156076847077556 image/jpeg 0
f20180111020739/j_JFO6xiir.json 1040 FmUhTchdLOd7LBoE8OXzPLDKcW60 15156077904192983 application/json 0
f20180111090619/i_1BwNksbL.jpg 49634 FtXBGmipcDha-67WQgGQR5shEBu2 15156329458714950 image/jpeg 0
f20180111090619/i_3BKlsRaZ.jpg 30152 FoWfMSuqz4TEQl5FT-FY5wqu5NGf 15156330575626044 image/jpeg 0
f20180111090619/i_5XboXSKh.jpg 40238 Fl84WaBWThHovIBsQaNFoIaPZcWh 15156329453409855 image/jpeg 0
f20180111090619/i_6DiYSBKp.jpg 74017 FrYG3icChRmFGnWQK6rYxa88KuQI 15156329461803290 image/jpeg 0
f20180111090619/i_76zaF2IM.jpg 38437 Fui8g5OrJh0GQqZzT9wtepfq99lJ 15156334738356648 image/jpeg 0
f20180111090619/i_B6TFYjks.jpg 37953 FleWqlK2W1ZmEgAatAEcm1gpR0kC 15156329464034474 image/jpeg 0
f20180111090619/i_N9eITqj3.jpg 38437 Fui8g5OrJh0GQqZzT9wtepfq99lJ 15156330419595764 image/jpeg 0
f20180111090619/i_QTSNWmA6.jpg 37953 FleWqlK2W1ZmEgAatAEcm1gpR0kC 15156333104224056 image/jpeg 0
f20180111090619/i_XdHcAfh1.jpg 56479 FjLQIQ3GxSEHDfu6tRcMylK1MZ05 15156334227270309 image/jpeg 0
f20180111090619/i_Xyy723MU.jpg 50076 FsfZpQzqu084RUw5NPYW9-Yfam_R 15156334229987458 image/jpeg 0
f20180111090619/i_d8Go0EOv.jpg 30152 FoWfMSuqz4TEQl5FT-FY5wqu5NGf 15156334736228515 image/jpeg 0
f20180111090619/i_diuHmX53.jpg 40591 FuTx1pw4idbKnV5MSvNGxCA5L470 15156333878320713 image/jpeg 0
f20180111090619/i_qQKzheSH.jpg 55858 Fj0A3i8V7fzzOiPQFL79ao15hkN9 15156329456666591 image/jpeg 0
f20180111090619/i_rHL5SYk8.jpg 40238 Fl84WaBWThHovIBsQaNFoIaPZcWh 15156336509742181 image/jpeg 0
f20180111090619/i_xZmQxUbz.jpg 40238 Fl84WaBWThHovIBsQaNFoIaPZcWh 15156333240603466 image/jpeg 0
f20180111090619/i_zBDNgXDv.jpeg 73616 FlgNwq8lypgsxrWs_ksrS_x47SQV 15156334232887875 image/jpeg 0
f20180111090619/j_4mxbEiVh.json 2990 Fpq-3yl3Yr1CadNrJVSDnpeRhQtT 15156331445226898 application/json 0
f20180111090619/j_i1K74768.json 3042 Fl5PpDw1TsZXMuhoq1RUrOeGZ6br 15156335067090003 application/json 0
f20180111095839/i_Q7KMKeda.png 518522 Fl-yB1_ruL2uxZN9k7DjB62h9dYH 15156359599713253 image/png 0
f20180111095839/j_5DpqHolV.json 184 FoYvi7cmSrzuVjUgCRzW5kU95SVo 15156359719719064 application/json 0
f20180111100442/i_No8kToIV.jpg 48975 Fu1cw3f--5Vpz9kLGeJfvljhCtyZ 15156364349642377 image/jpeg 0
f20180111100442/i_P1bkvSeg.jpg 68200 FvYe8vi46TjUKhEy_UwDqLhO6ZsW 15156363800690634 image/jpeg 0
f20180111100442/i_T1AulKcD.jpg 52641 Fj2YzvdC1n_1sF93ZZgrhF3OzOeY 15156364021186365 image/jpeg 0
f20180111100442/i_X8d8BN07.jpg 50770 FivwidMiHbogw77lqgkIKrgmF3eA 15156363969737156 image/jpeg 0
f20180111100442/i_g0wtOsCX.jpg 76656 Fmtixx0mP9CAUTNosjLuYQHL6k0P 15156363448222155 image/jpeg 0
f20180111100442/i_h5OT9324.jpg 72672 FvbIqPLTh2cQHTIBv2akUfahZa_Z 15156364401354652 image/jpeg 0
f20180111100442/i_he8iLYI6.jpg 49399 FjeJvwjwhU-hKZsq66UoBg9_tEJs 15156363907932480 image/jpeg 0
f20180111100442/i_kg29t7Pp.jpg 76293 FuYj__sSeEN7AsXMbxO24Z8Suh8d 15156364156384686 image/jpeg 0
f20180111100442/i_oz1YoBI1.jpg 75620 FkY3xsUMwOI01zgoH1iXXgiQeq6I 15156364089112904 image/jpeg 0
f20180111100442/i_xrOT98on.jpg 50021 Fql7ookM1Rc6V7VairKAfnKe-o9w 15156363856357316 image/jpeg 0
f20180111135114/i_Zqt8Tmoe.png 161629 FlELw59_mV3VqDBLyu1BKN4fIWnx 15156500155209863 image/png 0
f20180111135114/j_uhHoMXKq.json 159 FrypljwAr2LgoLAePBNTUYTUAgDt 15156500200488238 application/json 0
f20180111142119/i_s83iZ2GR.png 92278 Fns8tdh3JCkRmfE_COYEu4o8w03E 15156517082371259 image/png 0
f20180111142119/j_0g45JRth.json 159 Fq1rFwdRguYRXrp61nGZ5TsUG1V- 15156517143375596 application/json 0
f20180111144306/i_yE5TC84E.png 139230 Fjf61ymabEnEvnr5ZMHFjXGCrYlP 15156530038824150 image/png 0
f20180111144306/j_OF4WVtSH.json 159 FqwkKcxfo8jd0jFUyuH4X2CrnE9q 15156530083419530 application/json 0
f20180111150230/i_KtnER4g3.png 120044 FuwOWdrqzcr2-UScem-LzEMgMezs 15156541734892258 image/png 0
f20180111150230/j_xMSUEejY.json 158 FjJr_4deMqFphGaptm-2Pa6wwRP2 15156541771989216 application/json 0
f20180111151741/i_JuSWztB3.jpg 92506 FrIjRevHSi6xv4-NQa2wrHu5a1zQ 15156550875370965 image/jpeg 0
f20180111153550/i_9wWzVenl.gif 769872 FvslKY9JUaCQm-lu02E34tvAP_oG 15156561674621628 image/gif 0
'''

自己答案：

N0 = log.split('\n')
del N0[0],N0[-1]#删除首位上的空元素
N4 = []#将分割出来的内容存储
for i in range(len(N0)):
    N1 = N0[i].replace("\t",' ')
    N2 = N1.split(' ')
    N3 = N2[0].split('.')
    number = N2[1]
    style = N3[1]
    N4.append([style,number])
#print(N4)
jpeg = 0
json = 0
gif = 0
png = 0
for i in range(len(N4)):
    if N4[i][0] == 'jpeg':
        jpeg += jpeg + int(N4[i][1])
    elif N4[i][0] == 'json':
        json += json + int(N4[i][1])
    elif N4[i][0] == 'gif':
        gif = gif + int(N4[i][1])
    else:
        png = png + int(N4[i][1])
print('jpeg:' + str(jpeg))
print('json：' + str(json))
print('gif：' + str(gif))
print('png：' + str(png))

参考答案：

# 记录各种类型的文件的数量统计，存储格式如下
# [['jpg',4566],['json',4566]]
fileLenTable = []

# 根据文件类型找到记录对象,进行累加
def putRecordToTable(fileType,fileLen):
for one in fileLenTable:
if one[0] == fileType:
one[1] += fileLen
return

# 没有找到,创建一个记录元素
fileLenTable.append([fileType,fileLen])
return

for line in log.split('\n'):
if line.strip() == '':
continue

parts = line.split('\t')
name,size = parts[:2]

ext = name.split('.')[-1]

putRecordToTable(ext,int(size))

print(fileLenTable)

总结：