啤酒2元一瓶,2个空瓶能换一瓶,4个空瓶能换一瓶. 问: 10元最多能喝多少瓶?

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class Beer(object):     def __init__(self, money, price_money, price_bottle, price_cover):         self.money = money     # 钱数         self.price_money = price_money   # 每瓶花的钱         self.price_bottle = price_bottle  # 一瓶值的空瓶数         self.price_cover = price_cover   # 一瓶值的瓶盖数         self.beer = self.money // self.price_money         self.bottle = self.beer   # 瓶子         self.cover = self.bottle   # 盖子       def __repr__(self):         return f'喝酒数:{self.beer}, 剩下空瓶数:{self.bottle}, 剩下瓶盖数:{self.cover}'       def bottle_to_beer(self):         while self.bottle >= self.price_bottle:             add = self.bottle // self.price_bottle             self.beer += add             self.bottle += add             self.cover += add             self.bottle -= self.price_bottle * add       def cover_to_beer(self):         while self.cover >= self.price_cover:             add = self.cover // self.price_cover             self.beer += add             self.bottle += add             self.cover += add             self.cover -= self.price_cover * add     if __name__ == '__main__':     beer = Beer(money=10, price_money=2, price_bottle=2, price_cover=4)     while beer.bottle >= 2 or beer.cover >= 4:         beer.bottle_to_beer()         beer.cover_to_beer()     print(beer)