转换为大写金额

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  1  public static string CmycurD(double num)
  2         {
  3             string str1 = "零壹贰叁肆伍陆柒捌玖";               //0-9所对应的汉字
  4             string str2 = "万仟佰拾亿仟佰拾万仟佰拾元角分";     //数字位所对应的汉字
  5             string str3 = "";                                   //从原num值中取出的值
  6             string str4 = "";                                   //数字的字符串形式
  7             string str5 = "";                                   //人民币大写金额形式
  8             int j;                                              //num的值乘以100的字符串长度
  9             string ch1 = "";                                    //数字的汉语读法
 10             string ch2 = "";                                    //数字位的汉字读法
 11             int nzero = 0;                                      //用来计算连续的零值是几个
 12             int temp;                                           //从原num值中取出的值
 13 
 14             num = Math.Round(Math.Abs(num), 2);                 //将num取绝对值并四舍五入取2位小数
 15             str4 = (num * 100).ToString();                      //将num乘100并转换成字符串形式
 16             j = str4.Length;                                    //找出最高位
 17             if (j > 15)
 18             {
 19                 return "溢出";
 20             }
 21             str2 = str2.Substring(15 - j);                      //取出对应位数的str2的值。如：200.55,j为5所以str2=佰拾元角分
 22 
 23             //循环取出每一位需要转换的值
 24             for (int i = 0; i < j; i++)
 25             {
 26                 str3 = str4.Substring(i, 1);                    //取出需转换的某一位的值
 27                 temp = Convert.ToInt32(str3);                   //转换为数字         
 28                 if (i != (j - 3) && i != (j - 7) && i != (j - 11) && i != (j - 15))
 29                 {
 30                     //当所取位数不为元、万、亿、万亿上的数字时
 31                     if (str3 == "0")
 32                     {
 33                         ch1 = "";
 34                         ch2 = "";
 35                         nzero = nzero + 1;
 36                     }
 37                     else
 38                     {
 39                         if (str3 != "0" && nzero != 0)
 40                         {
 41                             ch1 = "零" + str1.Substring(temp * 1, 1);
 42                             ch2 = str2.Substring(i, 1);
 43                             nzero = 0;
 44                         }
 45                         else
 46                         {
 47                             ch1 = str1.Substring(temp * 1, 1);
 48                             ch2 = str2.Substring(i, 1);
 49                             nzero = 0;
 50                         }
 51                     }
 52                 }
 53                 else
 54                 {
 55                     //该位是万亿，亿，万，元位等关键位
 56                     if (str3 != "0" && nzero != 0)
 57                     {
 58                         ch1 = "零" + str1.Substring(temp * 1, 1);
 59                         ch2 = str2.Substring(i, 1);
 60                         nzero = 0;
 61                     }
 62                     else
 63                     {
 64                         if (str3 != "0" && nzero == 0)
 65                         {
 66                             ch1 = str1.Substring(temp * 1, 1);
 67                             ch2 = str2.Substring(i, 1);
 68                             nzero = 0;
 69                         }
 70                         else
 71                         {
 72                             if (str3 == "0" && nzero >= 3)
 73                             {
 74                                 ch1 = "";
 75                                 ch2 = "";
 76                                 nzero = nzero + 1;
 77                             }
 78                             else
 79                             {
 87                                 ch1 = "";
 88                                 ch2 = str2.Substring(i, 1);
 89                                 nzero = nzero + 1;
 91                             }
 92                         }
 93                     }
 94                 }
 95                 if (i == (j - 11) || i == (j - 3))
 96                 {
 97                     //如果该位是亿位或元位，则必须写上
 98                     ch2 = str2.Substring(i, 1);
 99                 }
100                 str5 = str5 + ch1 + ch2;
101                 if (i == j - 1 && str3 == "0")
102                 {
103                     //最后一位（分）为0时，加上“整”
104                     str5 = str5 + '整';
105                 }
106             }
107             if (num == 0)
108             {
109                 str5 = "零元整";
110             }
111             return str5;
112         }