非递归遍历二叉树Java版的实现代码(没写层次遍历)
直接上代码呵呵,里面有注解
package www.com.leetcode.specificProblem; import java.util.ArrayList; import java.util.List; import java.util.Stack; /** * 总结了三种非递归遍历二叉树 * @author 85060 * */ public class TraverseBinaryTree { //用来装遍历序列的一个list,展示的时候用 private List<TreeNode> helpList = new ArrayList<>(); public static void main(String[] args) { TreeNode root = createATree(); TraverseBinaryTree traverseBinaryTree = new TraverseBinaryTree(); //traverseBinaryTree.frontTraverseRecursion(root); //traverseBinaryTree.midTraverseRecursion(root); traverseBinaryTree.backTraverseRecursion(root); String rightAnswer = traverseBinaryTree.helpList.toString(); System.out.println("right: " + rightAnswer); traverseBinaryTree.helpList.clear(); //traverseBinaryTree.frontTravese(root); //traverseBinaryTree.midTraverse(root); traverseBinaryTree.backTraverse(root); String myAnswer = traverseBinaryTree.helpList.toString(); System.out.println("my ans: " + myAnswer); System.out.println("bingo? " + rightAnswer.equals(myAnswer)); } /** * 递归版的前序遍历二叉树 * @param node */ private void frontTraverseRecursion(TreeNode node) { if(node == null)return; helpList.add(node); frontTraverseRecursion(node.left); frontTraverseRecursion(node.right); } /** * 递归式的中序递归二叉树 * @param node */ private void midTraverseRecursion(TreeNode node) { if(node == null)return; midTraverseRecursion(node.left); helpList.add(node); midTraverseRecursion(node.right); } /** * 递归式的后序遍历二叉树 * @param node */ private void backTraverseRecursion(TreeNode node) { if(node == null)return; backTraverseRecursion(node.left); backTraverseRecursion(node.right); helpList.add(node); } /** * 非递归的前序遍历二叉树 * 用一个node,一直往左遍历,一边遍历一边入栈,当走到左边的尽头后,就出栈,然后去这个出栈元素的右子树,继续循环 * @param root */ private void frontTravese(TreeNode root) { if(root == null)return; Stack<TreeNode> stack = new Stack<TreeNode>(); TreeNode node = root; while(node != null || !stack.isEmpty()) { if(node != null) { helpList.add(node);//visit stack.push(node); node = node.left; } else { //左子树没了,进入栈中然后去右子树咯 node = stack.pop().right; } } } /** * 非递归式的中序递归二叉树 * @param root */ private void midTraverse(TreeNode root) { if(root == null)return ; Stack<TreeNode> stack = new Stack<TreeNode>(); TreeNode node = root; while(node != null || !stack.isEmpty()) { while(node != null) {//一直往左走到尽头 stack.push(node); node = node.left; } if(!stack.isEmpty()) { node = stack.pop(); helpList.add(node);//visit node = node.right;//进入右子树 } } } /** * 非递归的后序遍历二叉树 * 后序遍历的关键就是要判断上一个结点的右孩子访问了没,所以要存上次访问的结点 * @param root */ private void backTraverse(TreeNode root) { if(root == null)return; Stack<TreeNode> stack = new Stack<TreeNode>(); TreeNode node = root; TreeNode lastVisit = null;//记录刚刚访问过的那个结点,用来区分stack中pop出来的结点的右子树访问过没 while(node != null || !stack.isEmpty()) { while(node != null) {//一直走到树的最左边,stack是最左边的那个叶子结点 stack.push(node); node = node.left; } while(!stack.isEmpty()) { node = stack.peek(); if(node.right == null || node.right == lastVisit) {//没有右子树,右子树访问过了,都可以访问这个结点了 helpList.add(node);//visit //System.out.println(node); lastVisit = node; stack.pop(); if(stack.isEmpty())return;//这个很重要,不然会无限循环 } else {//右子树不为空,而且没访问过 node = node.right; break;//出去要走到这个右子树的最左边噢 } } } } /** * 构造一颗测试用的二叉树数据 * @return */ private static TreeNode createATree() { TreeNode root = new TreeNode(4); root.left = new TreeNode(3); root.right = new TreeNode(6); root.left.left = new TreeNode(11); root.left.right = new TreeNode(12); root.left.right.left = new TreeNode(45); root.right.left = new TreeNode(13); root.right.right = new TreeNode(14); root.right.right.right = new TreeNode(32); return root; } } /** * 二叉树结点类 * @author 85060 * */ class TreeNode { int data; TreeNode left; TreeNode right; public TreeNode(int data) { this.data = data; } @Override public String toString() { // TODO Auto-generated method stub return data + ""; } }