HDU 5916 Harmonic Value Description
Problem Description
The harmonic value of the permutation p1,p2,⋯pn is
Mr. Frog is wondering about the permutation whose harmonic value is the strictly k-th smallest among all the permutations of [n].
Mr. Frog is wondering about the permutation whose harmonic value is the strictly k-th smallest among all the permutations of [n].
Input
The first line contains only one integer T (1≤T≤100), which indicates the number of test cases.
For each test case, there is only one line describing the given integers n and k (1≤2k≤n≤10000).
For each test case, there is only one line describing the given integers n and k (1≤2k≤n≤10000).
Output
For each test case, output one line “Case #x: p1 p2 ⋯ pn”, where x is the case number (starting from 1) and p1 p2 ⋯ pn is the answer.
Sample Input
2
4 1
4 2
Sample Output
Case #1: 4 1 3 2
Case #2: 2 4 1 3
题目大意:给定一个数n,k,求出一个序列,使得他的和是第k小的(序列为1-n)
思路: 找出规律即可,当k=1时,直接按顺序输出1-n;k>1时 讲前2*k个数中的偶数和奇数分别放在一起,最后再将2*k+1 --- n 顺序输出即可
1 #include<iostream> 2 #include<algorithm> 3 #include<cstdio> 4 5 using namespace std; 6 int T,n,k; 7 int main() 8 { 9 scanf("%d",&T); 10 for(int t=1;t<=T;t++){ 11 scanf("%d%d",&n,&k); 12 printf("Case #%d:",t); 13 if(k>1){ 14 for(int i=2;i<=2*k;i+=2) 15 printf(" %d",i); 16 for(int i=1;i<2*k;i+=2) 17 printf(" %d",i); 18 for(int i=2*k+1;i<=n;i++) 19 printf(" %d",i); 20 }else{ 21 for(int i=1;i<=n;i++) 22 printf(" %d",i); 23 } 24 putchar('\n'); 25 } 26 return 0; 27 }