「杂题乱刷」CF1620E

合集 - 杂题乱刷(99)

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15.「杂题乱刷」CF1620E2023-12-14

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收起

一道好题。

题目链接

考虑离线操作。

我们可以设 $a_i$ 为当前 $i$ 表示的数字，然后直接倒序操作，运用并查集的思想，可以 $O(n)$ 通过此题。

参考代码：

#include<bits/stdc++.h>
using namespace std;
long long n,a[500010],id[500010],opt[500010],x[500010],y[500010],k;
#define map unordered_map
#define forl(i,a,b) for(register long long i=a;i<=b;i++)
#define forr(i,a,b) for(register long long i=a;i>=b;i--)
#define lc(x) x<<1
#define rc(x) x<<1|1
#define lowbit(x) x&-x
#define pb push_back
#define pf push_front
#define IOS ios::sync_with_stdio(0),cin.tie(0),cout.tie(0);
#define endl '\n'
#define QwQ return 0;
int main()
{
	IOS;
	forl(i,1,5e5)
		id[i]=i;
	cin>>n;
	forl(i,1,n)
	{
		cin>>opt[i];
		if(opt[i]==1)
			cin>>x[i];
		else
			cin>>x[i]>>y[i];
	}
	forr(i,n,1)
	{
		if(opt[i]==1)
			a[++k]=id[x[i]];
		else
			id[x[i]]=id[y[i]];
	}
	forr(i,k,1)
		cout<<a[i]<<" ";
	QwQ;
}