HDOJ 1228 A+B（map水题）

A + B

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 8539    Accepted Submission(s): 4810

Problem Description

读入两个小于100的正整数A和B,计算A+B.
需要注意的是:A和B的每一位数字由对应的英文单词给出.

 

 

Input

测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出. 

 

 

Output

对每个测试用例输出1行,即A+B的值.

 

 

Sample Input

one + two = three four + five six = zero seven + eight nine = zero + zero =

 

 

Sample Output

3 90 96

#include <iostream>
#include <string>
#include <map>
#include <utility>
using namespace std;

map <string, int> f;

int main() {
    int sum1, sum;
    string str;
    f["one"]=1;
    f["zero"]= 0;
    f["two"]= 2;
    f["three"] = 3;
    f["four"]=4;
    f["five"]=5;
    f["six"]=6;
    f["seven"]=7;
    f["eight"]=8;
    f["nine"]=9;
    while(1)
    {
        sum=0;
        while(1)
        {
            cin>>str;
            if(str=="+")
            break;
            sum=sum*10+f[str];
        }
        sum1=0;
        while(1)
        {
            cin>>str;
            if(str=="=")
            break;
            sum1=sum1*10+f[str];
        }
        
        if(sum==0 && sum1 ==0)
        break;
        cout <<sum+sum1<< endl;
    }
    return  0;
}