Excaliburer`s Zone

It was challenging, but not risky.

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//1.s型顺序访问二叉树,默认先左后右;利用两个栈来实现;如果先右后左的话,改变一下入栈的顺序就行
//2.注意s1 s2插入栈的顺序是不同的
void S_LevelOrderPrint(TreeNode t)
{
    stack<TreeNode> s1;
    stack<TreeNode> s2;
    s1.push(t);
    while(!s1.empty() || !s2.empty())
    {
        if(!s1.empty())
        {
            while(!s1.empty())
            {
                TreeNode tn = s1.top();
                cout<<tn.val<<"";
                s1.pop();
                if(tn.right != null)
                {
                    s2.push(tn.right);
                }
                if(tn.left != null)
                {
                    s2.push(tn.left);
                }
            }
        }
        else
        {
            while(!s2.empty())
            {
                TreeNode tn = s2.top();
                cout<<tn.val<<" ";
                s2.pop();
                if(tn.left != null)
                {
                    s1.push(tn.left);
                }
                if(tn.right != null)
                {
                    s1.push(tn.right);
                }
            }
        }

    }
}

  

  

posted on 2017-09-27 14:37  Excaliburer  阅读(1127)  评论(0编辑  收藏  举报