共享内存 进程通信
参考地址:http://www.ibm.com/developerworks/cn/linux/l-ipc/part5/index1.html?ca=drs-
main.c
/*-------------map_normalfile1.c-----------*/
#include <sys/mman.h>
#include <sys/types.h>
#include <fcntl.h>
#include <unistd.h>
typedef struct{
char name[4];
int age;
}people;
main(int argc, char** argv) // map a normal file as shared mem:
{
int fd,i;
people *p_map;
char temp;
fd=open(argv[1],O_CREAT|O_RDWR|O_TRUNC,00777);
lseek(fd,sizeof(people)*5-1,SEEK_SET);
write(fd,"",1);
p_map = (people*) mmap( NULL,sizeof(people)*10,PROT_READ|PROT_WRITE,
MAP_SHARED,fd,0 );
close( fd );
temp = 'a';
for(i=0; i<10; i++)
{
temp += 1;
memcpy( ( *(p_map+i) ).name, &temp,2 );
( *(p_map+i) ).age = 20+i;
}
printf(" initialize over \n ");
sleep(10);
munmap( p_map, sizeof(people)*10 );
printf( "umap ok \n" );
}
client.c
/*-------------map_normalfile2.c-----------*/
#include <sys/mman.h>
#include <sys/types.h>
#include <fcntl.h>
#include <unistd.h>
typedef struct{
char name[4];
int age;
}people;
main(int argc, char** argv) // map a normal file as shared mem:
{
int fd,i;
people *p_map;
fd=open( argv[1],O_CREAT|O_RDWR,00777 );
p_map = (people*)mmap(NULL,sizeof(people)*10,PROT_READ|PROT_WRITE,
MAP_SHARED,fd,0);
for(i = 0;i<10;i++)
{
printf( "name: %s age %d;\n",(*(p_map+i)).name, (*(p_map+i)).age );
}
munmap( p_map,sizeof(people)*10 );
}
Makefile
all:main
main:
gcc -g -Wall -O0 main.c -o main
client:
gcc -g -Wall -O0 client.c -o client
clean:
rm *.o main client
分别把两个程序编译成可执行文件map_normalfile1和map_normalfile2后,在一个终端上先运行./map_normalfile2 /tmp/test_shm,程序输出结果如下:
initialize over umap ok |
在map_normalfile1输出initialize over 之后,输出umap ok之前,在另一个终端上运行map_normalfile2 /tmp/test_shm,将会产生如下输出(为了节省空间,输出结果为稍作整理后的结果):
name: b age 20; name: c age 21; name: d age 22; name: e age 23; name: f age 24; name: g age 25; name: h age 26; name: I age 27; name: j age 28; name: k age 29; |
在map_normalfile1 输出umap ok后,运行map_normalfile2则输出如下结果:
name: b age 20; name: c age 21; name: d age 22; name: e age 23; name: f age 24; name: age 0; name: age 0; name: age 0; name: age 0; name: age 0; |