python 中使用 urllib2 伪造 http 报头的2个方法

方法1、

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#!/usr/bin/python
# -*- coding: utf-8 -*-
#encoding=utf-8
#Filename:urllib2-header.py
  
import urllib2
import sys
  
#抓取网页内容-发送报头-1
send_headers = {
 'Host':'www.jb51.net',
 'User-Agent':'Mozilla/5.0 (Windows NT 6.2; rv:16.0) Gecko/20100101 Firefox/16.0',
 'Accept':'text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8',
 'Connection':'keep-alive'
}
  
req = urllib2.Request(url,headers=send_headers)
r = urllib2.urlopen(req)
  
html = r.read()        #返回网页内容
receive_header = r.info()     #返回的报头信息
  
# sys.getfilesystemencoding()
html = html.decode('utf-8','replace').encode(sys.getfilesystemencoding()) #转码:避免输出出现乱码
  
print receive_header
# print '####################################'
print html

方法2、

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#!/usr/bin/python
# -*- coding: utf-8 -*-
#encoding=utf-8
#Filename:urllib2-header.py
  
import urllib2
import sys
  
  
req = urllib2.Request(url)
req.add_header('Referer','http://www.jb51.net/')
req.add_header('User-Agent','Mozilla/5.0 (Windows NT 6.2; rv:16.0) Gecko/20100101 Firefox/16.0')
r = urllib2.urlopen(req)
  
html = r.read()
receive_header = r.info()
  
html = html.decode('utf-8').encode(sys.getfilesystemencoding())
  
print receive_header
print '#####################################'
print html
posted @ 2018-05-09 21:42  salami_china  阅读(190)  评论(0编辑  收藏  举报