ProjectEuler 006题

题目：

The sum of the squares of the first ten natural numbers is,

1² + 2² + ... + 10² = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)² = 55² = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

这个也太简单了，不过如果用笔算的话肯定很难，需要思考一番

#include<iostream>
using namespace std;

int main() {
    int N = 100;
    int squareofsum = ((1+N)*N/2)*((1+N)*N/2);
    int sumofaquare = 0;
    for(int i = 1; i <= N; i++) {
        sumofaquare += i*i;
    }
    cout << squareofsum - sumofaquare << endl;
    system("pause");
    return 0;
}