1005. Spell It Right (20)

Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.

Input Specification:

Each input file contains one test case. Each case occupies one line which contains an N (<= 10¹⁰⁰).

Output Specification:

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

Sample Input:

12345

Sample Output:

one five

#include<cstdio>
#include<cstring>
int main(){
    char s[110];
    gets(s);  //gets（）因为不安全已经被PAT禁用了
    int sum = 0, len = strlen(s);
    for(int i = 0; i < len; i++){
        sum += (s[i] - '0');
    }
    int ans[100],num = 0;
    do{
        ans[num++] = sum % 10;
        sum /= 10;
    }while(sum != 0);
    
    char word[10][10] = {
        "zero","one","two","three","four","five","six","seven","eight","nine" 
    };
    for(int j = num - 1; j >= 0; j--){
        printf("%s",word[ans[j]]);
        if(j > 0) printf(" ");
        else printf("\n");
        
    }
} 

 

// 0 要特判 
#include<iostream>
#include<string>
using namespace std;
char digit[11][10] = {
 "zero","one","two","three","four","five","six","seven","eight","nine"
};
int main(){
    string str;
    getline(cin,str);
    int sum,num[110],n = 0;
    for(int i = 0; i < str.length(); i++){
        sum += (str[i] - '0');
    }
    if(sum == 0) cout << "zero";
    else {
    while(sum > 0){
        num[n++] = sum % 10;
        sum /= 10;
    }
}
    for(int i = n - 1; i>= 0; i--){
        cout << digit[num[i]];
        if(i > 0) cout << " ";
    }
    return 0;
}