04-树6 Complete Binary Search Tree (30 分)

A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties:

 

  • The left subtree of a node contains only nodes with keys less than the node's key.

     

     

  • The right subtree of a node contains only nodes with keys greater than or equal to the node's key.

     

     

  • Both the left and right subtrees must also be binary search trees.

     

    A Complete Binary Tree (CBT) is a tree that is completely filled, with the possible exception of the bottom level, which is filled from left to right.

    Now given a sequence of distinct non-negative integer keys, a unique BST can be constructed if it is required that the tree must also be a CBT. You are supposed to output the level order traversal sequence of this BST.

    Input Specification:

    Each input file contains one test case. For each case, the first line contains a positive integer N (≤). Then N distinct non-negative integer keys are given in the next line. All the numbers in a line are separated by a space and are no greater than 2000.

    Output Specification:

    For each test case, print in one line the level order traversal sequence of the corresponding complete binary search tree. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line.

    Sample Input:

    10
    1 2 3 4 5 6 7 8 9 0
    

    Sample Output:

    6 3 8 1 5 7 9 0 2 4
    #include<cstdio>
    #include<algorithm>
    using namespace std;
    const int maxn = 1010;
    int CBT[maxn],index = 0,num[maxn];
    int n;
    
    void inOrder(int root){
        if(root > n) return;
        inOrder(root*2);
        CBT[root] = num[index++];
        inOrder(root*2+1);
    }
    
    int main(){
        scanf("%d",&n);
        for(int i = 0; i < n; i++){
            scanf("%d",&num[i]);
        }
        sort(num,num+n);
        inOrder(1);
        for(int i = 1; i <= n; i++){
            printf("%d",CBT[i]);
            if(i < n) printf(" ");
        }
        return 0;
    }

     

posted @ 2019-02-20 21:27  王清河  阅读(215)  评论(0编辑  收藏  举报