ural 1076 KM求最小权匹配

贴模板~

KM算法引进了顶标函数,不断缩小这个顶标来让相等子图的可能范围扩大

#include<iostream>
#include<cstring>
//KM 复杂度O^3 
using namespace std;
const int N=200;
int lx[N],ly[N];//顶标函数
int w[N][N];//
bool vix[N],viy[N];
int linky[N];//
int lack;//每次顶标函数扩大的增量
int n,m;
bool find(int x){
    vix[x]=1;
    for(int y=1;y<=m;y++){
        if(viy[y])continue;
        int t=lx[x]+ly[y]-w[x][y];
        if(t==0){
            viy[y]=1;
            if(linky[y]==0||find(linky[y])){
                linky[y]=x;
                return true;
            }
        }else lack=min(lack,t);
    }
    return false;
}
int KM(){
   memset(linky,0,sizeof(linky));
   memset(lx,0,sizeof(lx));
   memset(ly,0,sizeof(ly));
   for(int i=1;i<=n;i++){
       for(int j=1;j<=m;j++){
           lx[i]=max(lx[i],w[i][j]);//顶标函数一般初始化为lx取从i出发的边的最大值,ly为0  
       }
   }
   for(int x=1;x<=n;x++){
        while(true){
            memset(vix,0,sizeof(vix));
            memset(viy,0,sizeof(viy));
            lack=INF;
            if(find(x))break;
            for(int i=1;i<=n;i++){
                if(vix[i])lx-=lack;
            }
            for(int i=1;i<=m;i++){
                if(viy[i])ly[i]+=lack;
            }
        }
   }
   int ret=0;
   for(int y=1;y<=m;y++){
      if(linky[y]>0)ret+=w[linky[y]][y];
   }
   return ret;
}

 

 

//注释掉的那份有时后老师tle。。复杂度都一样呀好tm奇怪
int n;
int match[N];
double lx[N],ly[N],w[N][N],slack[N];
double lack;
const double eps = 1e-5;
bool vix[N],viy[N];

/*
bool find(int x){
    vix[x]=1;
    fab(y,1,n){
        if(viy[y])continue;
        double t=lx[x]+ly[y]-w[x][y];
        if(fabs(t)<=eps){
            viy[y]=1;
            if(match[y]==-1||find(match[y])){
                match[y]=x;
                return 1;
            }
        }else lack=min(lack,t);
    }
    return 0;
}
void KM(){
    memset(match,-1,sizeof match);
    fab(i,1,n)ly[i]=0;
    fab(i,1,n){
        lx[i]=-INF;
        fab(j,1,n)lx[i]=max(lx[i],w[i][j]);
    }
    fab(x,1,n){
        while(true){
            memset(vix,0,sizeof vix);
            memset(viy,0,sizeof viy);
            lack=INF;
            if(find(x))break;
            fab(i,1,n){
                if(vix[i])lx[i]-=lack;
                if(viy[i])ly[i]+=lack;
            }
        }
    }
}*/
bool dfs(int x){
    vix[x]=1;
    fab(y,1,n){
        if(viy[y])continue;
        double t=lx[x]+ly[y]-w[x][y];
        if(fabs(t)<=eps){
            viy[y]=1;
            if(match[y]==-1||dfs(match[y])){
               match[y]=x;
               return 1;
            }
        }else slack[y]=min(slack[y],t);
    }
    return 0;
}
void KM(){
    memset(match,-1,sizeof match);
    fab(i,1,n)ly[i]=0;
    fab(i,1,n){
        lx[i]=-INF;
        fab(j,1,n){
            lx[i]=max(lx[i],w[i][j]);
        }
    }
    fab(x,1,n){
        fab(i,1,n)slack[i]=INF;
        while(true){
            memset(vix,0,sizeof vix);
            memset(viy,0,sizeof viy);
            if(dfs(x))break;
            double d=INF;
            fab(i,1,n)if(!viy[i]&&d>slack[i])d=slack[i];
            fab(i,1,n)if(vix[i])lx[i]-=d;
            fab(i,1,n)if(viy[i])ly[i]+=d;else slack[i]-=d;
        }
    }
}

 

ural 1076 练练手

//ural 1076 
#include<iostream>
#include<iomanip>
#include<cstring>
#include<stdio.h>
#include<map>
#include<cmath>
#include<algorithm>
#include<vector>
#include<stack>
#include<fstream>
#include<queue>
#define rep(i,n) for(int i=0;i<n;i++)
#define fab(i,a,b) for(int i=(a);i<=(b);i++)
#define fba(i,b,a) for(int i=(b);i>=(a);i--)
#define MP make_pair
#define PB push_back
#define cls(x) memset(x,0,sizeof(x))
#define lowbit(x) x&-x
#define INF 0x7ffffff
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
using namespace std;
const int N=160;
int n,lack;
int l[N],r[N],adj[N][N],match[N];
bool vix[N],viy[N];
void init(){
    cls(vix);
    cls(viy);
    cls(adj);
    cls(l);
    cls(r);
    memset(match,-1,sizeof(match));
}
bool find(int x){
    vix[x]=1;
    fab(y,1,n){
        if(viy[y])continue;
        int t=l[x]+r[y]-adj[x][y];
        if(t==0){
            viy[y]=1;
            if(match[y]==-1||find(match[y])){
                match[y]=x;
                return true;
            }
        }else lack=min(lack,t);
    }
    return false;
}
int KM(){
    fab(i,1,n){
        l[i]=-INF;
        fab(j,1,n){
            l[i]=max(l[i],adj[i][j]);
        }
    }
    fab(i,1,n){
        while(true){
            cls(vix);
            cls(viy);
            lack=INF;
            if(find(i))break;
            fab(i,1,n){
                if(vix[i])l[i]-=lack;
            }
            fab(i,1,n){
                if(viy[i])r[i]+=lack;
            }
        }
    }
    int ret=0;
    fab(i,1,n){
        if(match[i]!=-1)ret+=adj[match[i]][i];
    }
    return ret;
}
int main(){
    ios::sync_with_stdio(false);
    init();
    scanf("%d",&n);
    fab(i,1,n){
        int sum=0;
        fab(j,1,n){
            scanf("%d",&adj[i][j]);
            sum+=adj[i][j];
        }
        fab(j,1,n){
            adj[i][j]=sum-adj[i][j];
        }
    }
    fab(i,1,n)fab(j,1,n)adj[i][j]=-adj[i][j];
    printf("%d\n",-KM());
    return 0;
}

posted on 2014-05-31 17:27  wanggp3  阅读(278)  评论(0编辑  收藏  举报

导航