java箭头函数,lambda表达式

jdk8+以上引入了箭头函数,即J8的lambda表达式。

// 1. 不需要参数,返回值为 5  
() -> 5  
  
// 2. 接收一个参数(数字类型),返回其2倍的值  
x -> 2 * x  
  
// 3. 接受2个参数(数字),并返回他们的差值  
(x, y) -> x – y  
  
// 4. 接收2个int型整数,返回他们的和  
(int x, int y) -> x + y  
  
// 5. 接受一个 string 对象,并在控制台打印,不返回任何值(看起来像是返回void)  
(String s) -> System.out.print(s)




String[] atp = {"Rafael Nadal", "Novak Djokovic",  
       "Stanislas Wawrinka",  
       "David Ferrer","Roger Federer",  
       "Andy Murray","Tomas Berdych",  
       "Juan Martin Del Potro"};  
List<String> players =  Arrays.asList(atp);  
  
// 以前的循环方式  
for (String player : players) {  
     System.out.print(player + "; ");  
}  
  
// 使用 lambda 表达式以及函数操作(functional operation)  
players.forEach((player) -> System.out.print(player + "; "));  
   
// 在 Java 8 中使用双冒号操作符(double colon operator)  
players.forEach(System.out::println);





String[] players = {"Rafael Nadal", "Novak Djokovic",   
    "Stanislas Wawrinka", "David Ferrer",  
    "Roger Federer", "Andy Murray",  
    "Tomas Berdych", "Juan Martin Del Potro",  
    "Richard Gasquet", "John Isner"};  
   
// 1.1 使用匿名内部类根据 name 排序 players  
Arrays.sort(players, new Comparator<String>() {  
    @Override  
    public int compare(String s1, String s2) {  
        return (s1.compareTo(s2));  
    }  
});




// 1.2 使用 lambda expression 排序 players  
Comparator<String> sortByName = (String s1, String s2) -> (s1.compareTo(s2));  
Arrays.sort(players, sortByName);  
  
// 1.3 也可以采用如下形式:  
Arrays.sort(players, (String s1, String s2) -> (s1.compareTo(s2)));

  

posted on 2020-07-02 10:27  王大慧  阅读(2886)  评论(0编辑  收藏  举报