摘要:
public ListNode GetIntersectionNode(ListNode headA, ListNode headB) { var pointA = headA; var pointB = headB; if(headA != null && headB != null) { while(p... 阅读全文
摘要:
https://blog.csdn.net/Miss_yuki/article/details/81304107 关于环形的解析 阅读全文
摘要:
https://leetcode.com/problems/design-linked-list/class ListNode { int val; ListNode next; ListNode (int val) {this.val = val;} } class MyLinkedList { ListNode head=null; /** Init... 阅读全文