springboot 存在superBuilder时使用Mapstruct

问题

springboot在使用mapstruct对对象进行转换时遇到一个问题，即在对象使用了@SuperBuilder注解时mapstruct生成的转换类会报错（Mapper放在涉及转换的类内，另外写class不会报错），报错如下

@Data
@SuperBuilder(toBuilder = true)
@AllArgsConstructor
@NoArgsConstructor
public class TestSuperClass {

    private String column1;
    private String column2;

}

@EqualsAndHashCode(callSuper = true)
@Data
@SuperBuilder(toBuilder = true)
@AllArgsConstructor
@NoArgsConstructor
public class TestClass extends TestSuperClass{

    private String column3;
    private String column4;

    @Mapper(unmappedTargetPolicy = ReportingPolicy.IGNORE)
    public interface TestClassModelMapper {        
        TestTargetClass doToTarget(TestClass testClass);
    }

    public static final TestClassModelMapper INSTANCE = Mappers.getMapper(TestClassModelMapper.class);
}

@Data
@Builder
@AllArgsConstructor
@NoArgsConstructor
public class TestTargetClass {

    private String column1;
    private String column2;
    private String column3;
    private String column4;

}

以上为各实体类

@Generated(
    value = "org.mapstruct.ap.MappingProcessor",
    date = "2021-07-06T15:28:32+0800",
    comments = "version: 1.4.2.Final, compiler: javac, environment: Java 1.8.0_251 (Oracle Corporation)"
)
public class TestClass$TestClassModelMapperImpl implements TestClassModelMapper {

    @Override
    public TestTargetClass doToTarget(TestClass testClass) {
        if ( testClass == null ) {
            return null;
        }

        TestTargetClassBuilder testTargetClass = TestTargetClass.builder();

        testTargetClass.column1( testClass.getColumn1() );
        testTargetClass.column2( testClass.getColumn2() );
        testTargetClass.column3( testClass.getColumn3() );
        testTargetClass.column4( testClass.getColumn4() );

        return testTargetClass.build();
    }

    @Override
    public TestClass doToDo(TestClass testClass) {
        if ( testClass == null ) {
            return null;
        }

        TestSuperClassBuilder<?, ?> testClass1 = TestSuperClass.builder();

        testClass1.column1( testClass.getColumn1() );
        testClass1.column2( testClass.getColumn2() );

        return testClass1.build();
    }
}

以上为mapstruct生成的转换class，很明显生成的转换类内调用了父类的Builder导致返回类型错误

解决方案

在TestClass内部Mapper的注解@Mapper内添加参数builder = @Builder(disableBuilder = true)，即

@EqualsAndHashCode(callSuper = true)
@Data
@SuperBuilder(toBuilder = true)
@AllArgsConstructor
@NoArgsConstructor
public class TestClass extends TestSuperClass implements Serializable {
    private static final long serialVersionUID = 1L;

    private String column3;
    private String column4;

    @Mapper(unmappedTargetPolicy = ReportingPolicy.IGNORE, builder = @Builder(disableBuilder = true))
    public interface TestClassModelMapper {
        TestTargetClass doToTarget(TestClass testClass);

        TestClass doToDo(TestClass testClass);
    }

    public static TestClass.TestClassModelMapper INSTANCE = Mappers.getMapper(TestClass.TestClassModelMapper.class);
}