面试题19 二叉树的镜像

题目描述

操作给定的二叉树，将其变换为源二叉树的镜像。

/*
struct TreeNode {
    int val;
    struct TreeNode *left;
    struct TreeNode *right;
    TreeNode(int x) :
            val(x), left(NULL), right(NULL) {
    }
};*/
class Solution {
public:
    void Mirror(TreeNode *pRoot) {
        if (pRoot){
            TreeNode *node = pRoot->left;
            pRoot->left = pRoot->right;
            pRoot->right = node;
            Mirror(pRoot->left);
            Mirror(pRoot->right);
        }
    }
};