每日一题 2019.9.24

# coding=utf-8
"""求1+2!+3!+...+20!的和."""


def getNumStep(num):
    if num == 1:
        return 1
    else:
        return num * getNumStep(num - 1)

if __name__ == '__main__':
    sum = 0
    for i in range(1, 21):
        sum += getNumStep(i)
    print(sum)

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