mysql使用json类型字段

测试版本:8.0.15

 

数据库数据:

 

 

1. 查询json中某个字段 精准查询

SELECT * FROM `tb_json` WHERE JSON_EXTRACT(`Remarks`, '$.name') = 'zhangsan';

或者

SELECT * FROM `tb_json` WHERE JSON_CONTAINS(Remarks,JSON_OBJECT('name','zhangsan'));

结果:

 

 2.查询嵌套对象某个字段  精准查询

SELECT * FROM `tb_json` WHERE JSON_EXTRACT(`Remarks`, '$.address.city') = 'rizhao';

 

结果:

 

 

3.查询json中某个字段 模糊查询

SELECT * FROM `tb_json` WHERE JSON_EXTRACT(`Remarks`, '$.name') LIKE '%zhangsan%';

 

SELECT * FROM `tb_json` WHERE JSON_EXTRACT(`Remarks`, '$.age') >= 25;

结果:

 

posted @ 2021-08-16 15:35  DarryRing  阅读(882)  评论(0编辑  收藏  举报