hdu 1497(图书管理系统模拟）
题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=1497
思路：就是一个简单的图书管理系统模拟，book的布尔值显示是否在图书馆；如果有一个人还书，那么那个人的拥有书的信息也要修改。
View Code
1 #include<iostream> 2 #include<cstdio> 3 #include<cstring> 4 #include<algorithm> 5 using namespace std; 6 #define MAXN 100000+10 7 bool book[MAXN]; 8 int n,m; 9 struct Person{ 10 int book[11]; 11 int _count; 12 }Per[MAXN/10]; 13 14 15 int main(){ 16 int _case; 17 while(~scanf("%d%d",&n,&m)){ 18 memset(book,true,sizeof(book)); 19 memset(Per,0,sizeof(Per)); 20 scanf("%d",&_case); 21 while(_case--){ 22 char str[10]; 23 scanf("%s",str); 24 int x,y; 25 if(str[0]=='R'){ 26 scanf("%d",&x); 27 if(book[x]){puts("The book is already in the library");continue;} 28 else { 29 book[x]=true; 30 puts("Return success"); 31 bool flag=true; 32 for(int i=1;i<=m&&flag;i++){ 33 int k=Per[i]._count; 34 for(int j=1;j<=k;j++)if(Per[i].book[j]==x){ 35 for(int l=j+1;l<=k;l++){Per[i].book[l-1]=Per[i].book[l];} 36 Per[i]._count--; 37 flag=false; 38 break; 39 } 40 } 41 } 42 }else if(str[0]=='B'){ 43 scanf("%d%d",&x,&y); 44 int count; 45 if(!book[y]){puts("The book is not in the library now");continue;} 46 else if(Per[x]._count==9){puts("You are not allowed to borrow any more");continue;} 47 else {book[y]=false;count=++Per[x]._count;Per[x].book[count]=y;puts("Borrow success");continue;} 48 }else { 49 scanf("%d",&x); 50 if(Per[x]._count==0){puts("Empty");continue;} 51 else { 52 sort(Per[x].book+1,Per[x].book+Per[x]._count+1); 53 for(int i=1;i<Per[x]._count;i++){ 54 printf("%d ",Per[x].book[i]); 55 } 56 printf("%d\n",Per[x].book[Per[x]._count]); 57 } 58 } 59 } 60 puts(""); 61 } 62 return 0; 63 }
