hdu 1497(图书管理系统模拟）

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=1497

思路：就是一个简单的图书管理系统模拟，book的布尔值显示是否在图书馆；如果有一个人还书，那么那个人的拥有书的信息也要修改。

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
#define MAXN 100000+10
bool book[MAXN];
int n,m;
struct Person{
    int book[11];
    int _count;
}Per[MAXN/10];


int main(){
    int _case;
    while(~scanf("%d%d",&n,&m)){
        memset(book,true,sizeof(book));
        memset(Per,0,sizeof(Per));
        scanf("%d",&_case);
        while(_case--){
            char str[10];
            scanf("%s",str);
            int x,y;
            if(str[0]=='R'){
                scanf("%d",&x);
                if(book[x]){puts("The book is already in the library");continue;}
                else {
                    book[x]=true;
                    puts("Return success");
                    bool flag=true;
                    for(int i=1;i<=m&&flag;i++){
                        int k=Per[i]._count;    
                        for(int j=1;j<=k;j++)if(Per[i].book[j]==x){
                            for(int l=j+1;l<=k;l++){Per[i].book[l-1]=Per[i].book[l];}
                            Per[i]._count--;
                            flag=false;
                            break;
                        }
                    }
                }
            }else if(str[0]=='B'){
                scanf("%d%d",&x,&y);
                int count;
                if(!book[y]){puts("The book is not in the library now");continue;}
                else if(Per[x]._count==9){puts("You are not allowed to borrow any more");continue;}
                else {book[y]=false;count=++Per[x]._count;Per[x].book[count]=y;puts("Borrow success");continue;}
            }else {
                scanf("%d",&x);
                if(Per[x]._count==0){puts("Empty");continue;}
                else {
                    sort(Per[x].book+1,Per[x].book+Per[x]._count+1);
                    for(int i=1;i<Per[x]._count;i++){
                        printf("%d ",Per[x].book[i]);
                    }
                    printf("%d\n",Per[x].book[Per[x]._count]);
                }
            }
        }
        puts("");
    }
    return 0;
}