Algorithms

  1. Count prime numbers not exceeding n(n>0)
  2. Pseudocode:
    Input: an integer n > 1 Let A be an array of Boolean values, indexed by integers 2 to n, initially all set to true. for i = 2, 3, 4, ..., not exceeding √n: if A[i] is true: for j = i2, i2+i, i2+2i, i2+3i, ..., not exceeding n : A[j] := false Output: all i such that A[i] is true.

    The Sieve of Eratosthenes uses an extra O(n) memory and its runtime complexity is O(n log log n).

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posted @ 2015-06-11 03:33  wxwcase  阅读(172)  评论(0编辑  收藏  举报