Algorithms
- Count prime numbers not exceeding n(n>0)
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Pseudocode:
Input: an integer n > 1 Let A be an array of Boolean values, indexed by integers 2 to n, initially all set to true. for i = 2, 3, 4, ..., not exceeding √n: if A[i] is true: for j = i2, i2+i, i2+2i, i2+3i, ..., not exceeding n : A[j] := false Output: all i such that A[i] is true.The Sieve of Eratosthenes uses an extra O(n) memory and its runtime complexity is O(n log log n).
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