数学建模例题2.13 数据分组

`
def bifurcate_by(L,fn):
return [[x for x in L if fn(x)],
[x for x in L if not fn(x)]]
s = bifurcate_by(['beep','boop','foo','bar'],lambda x:x[0]=='b')
print(s)

print("学号：3005")
`