摘要：
证明：从题目可以知道 A: (1 + x2/1! + x4/2! + ....); B: (1 + x/1! + x2/2! + x3/3! + ...); C:(1 + x2/1! + x4/2! + ....); D: (1 + x/1! + x2/2! + x3/3! + ...);所以有： G(x) = (1 + x2/1! + x4/2! + ....)2 * (1 + x/1! + x2/2! + x3/3! + ...)2;由于泰勒展开式：ex = 1 + x/1! + x2/2! + x3/3! + ...e-x = 1 - x/1! + x2/2! - x3/3! + ... 阅读全文