C.char字符串的拼接和const char*的转换
C里没有String类型
要用char[]来代替String的职能
上代码：
1 #include <stdio.h> 2 #include <string.h> 3 4 int main(void) 5 { 6 const char *p1; 7 char str1[] = "hello"; 8 char str2[] = " world"; 9 char newStr[50] = ""; 10 strcat(newStr, "good,"); //直接把字符串添加到newStr 11 strcat(newStr, str1); //str1添（追）加到newStr 12 strcat(newStr, str2); //str2添（追）加到newStr 13 p1 = newStr; //char可以直接赋值给const char* 14 printf("p1: %s\n", p1); 15 printf("p1.length(err): %d\n", sizeof(p1)); //这个获取的长度并不是真实字符串长度 16 printf("p1.length: %d\n", getLength(p1)); 17 printf("str1.length: %d \n", sizeof(str1)); //(含字符串尾部的结束符\0，所以长度要加1) 18 printf("str2.length: %d\n", sizeof(str2)); 19 printf("newStr.length: %d \n", sizeof(newStr)); //(按实际定义的数组长度) 20 ｝
运行结果：
p1: good,hello world p1.length(err): 8 p1.length: 16 str1.length: 6 str2.length: 7 newStr.length: 50
