[LeetCode]Compare Version Numbers

刚从微软onsite回来,感觉要跪了。不过doesnt matter 继续刷题面谷歌

很有意思的一道小题,很容易出错

public class Solution {
    public int compareVersion(String version1, String version2) {
        String[] v1 = version1.split("\\.");
        String[] v2 = version2.split("\\.");
        for (int i = 0; i < Math.max(v1.length, v2.length); i++) {
            int tmp1 = i < v1.length ? Integer.valueOf(v1[i]) : 0;
            int tmp2 = i < v2.length ? Integer.valueOf(v2[i]) : 0;
            if (tmp1 != tmp2) {
                return tmp1 > tmp2 ? 1 : -1;
            }
        }
        return 0;
    }
}

 

posted @ 2015-12-11 11:59  Weizheng_Love_Coding  阅读(113)  评论(0编辑  收藏  举报