模拟Djangoweb框架

一、需求

　　1.访问127.0.0.1/login，访问到login页面

　　2.登陆成功，跳转到登陆后的页面

　　3.登陆失败，跳转到登陆失败的页面

　　4.用户账号密码验证

二、目录结构

　　

三、代码

　　day01.py

from wsgiref.simple_server import make_server

def foo1(request):
    f = open("egon.html", 'rb')
    data = f.read()
    f.close()
    return [data]

def foo2(request):
    f = open("alex.html", 'rb')
    data = f.read()
    return [data]

def login(request):
    f = open("login.html", 'rb')
    data = f.read()
    return [data]

def login_after(request):
    f = open("login_after.html", 'rb')
    data = f.read()
    return [data]

def login_error(request):
    f = open("login_error.html", 'rb')
    data = f.read()
    return [data]

def auth(request):
    user_union, password_union = request.get('QUERY_STRING').split('&')
    _, username = user_union.split("=")
    _, password = password_union.split("=")
    if username == 'chenwei' and password == '123':
        return login_after(request)
    else:
        return login_error(request)

def routers():
    urlpattern = [
        ('/login', login),
        ('/egon', foo1),
        ('/alex', foo2),
        ('/auth', auth),
    ]
    return urlpattern

def applicaion(environ,start_response):
    path = environ.get('PATH_INFO')
    start_response('200 OK', [('Content-Type', 'text/html')])
    urlpattern = routers()
    func = None

    for item in urlpattern:
        if path == item[0]:
            func = item[1]
            break
    if func:
        return func(environ)
    else:
        return [b'404']

t = make_server("", 8080, applicaion)
t.serve_forever()

　　alex.html

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta http-equiv="x-ua-compatible" content="IE=edge">
    <meta name="viewport" content="width=device-width, initial-scale=1">
    <title>Title</title>
</head>
<body>
<h1>welcome Alex</h1>
</body>
</html>

　　egon.html

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta http-equiv="x-ua-compatible" content="IE=edge">
    <meta name="viewport" content="width=device-width, initial-scale=1">
    <title>Title</title>
</head>
<body>
<h1>Welcome egon</h1>
</body>
</html>

　　login.html

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta http-equiv="x-ua-compatible" content="IE=edge">
    <meta name="viewport" content="width=device-width, initial-scale=1">
    <title>Title</title>
</head>
<body>

<h1>登陆页面</h1>
<form action="http://localhost:8080/auth">
    <p>用户名：<input type="text" name="username"/></p>
    <p>密码：<input type="password" name="password"/></p>
    <p>提交：<input type="submit"/></p>
</form>
</body>
</html>

　　login_after.html

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta http-equiv="x-ua-compatible" content="IE=edge">
    <meta name="viewport" content="width=device-width, initial-scale=1">
    <title>Title</title>
</head>
<body>
<h1 style="color: red">登陆后页面跳转</h1>
</body>
</html>

　　login_error.html

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta http-equiv="x-ua-compatible" content="IE=edge">
    <meta name="viewport" content="width=device-width, initial-scale=1">
    <title>Title</title>
</head>
<body>
<h1 style="color: yellow">登陆失败的页面</h1>
</body>
</html>

四、代码优化

　　当我们在浏览器上输入一个url，实际上是向服务器发起一次get请求,而当我们提交数据的时候，通过post发送请求，因此我们可以通过判断第一次请求是否为post请求，来判断，用户是在提交表单还是在请求网页。所以，上述的day01.py代码，auth验证可以和login整合在一起。

def login(request):
    if request.method == 'POST':
        user_union, password_union = request.get('QUERY_STRING').split('&')
        _, username = user_union.split("=")
        _, password = password_union.split("=")
        if username == 'chenwei' and password == '123':
            return login_after(request)
        else:
            return login_error(request)

    f = open("login.html", 'rb')
    data = f.read()
    return [data]

五、流程解析

　　　　

 

posted @ 2017-08-21 14:17  看雪。  阅读(271)  评论(0)  编辑  收藏  举报