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oracle direction目录

Create directory让我们可以在Oracle数据库中灵活的对文件进行读写操作,极大的提高了Oracle的易用性和可扩展性。
其语法为:
CREATE [OR REPLACE] DIRECTORY directory AS 'pathname';

本案例具体创建如下:

create or replace directory exp_dir as '/tmp';

目录创建以后,就可以把读写权限授予特定用户,具体语法如下:
GRANT READ[,WRITE] ON DIRECTORY directory TO username;

例如:

grant read, write on directory exp_dir to eygle;

此时用户eygle就拥有了对该目录的读写权限。

让我们看一个简单的测试:

SQL> create or replace directory UTL_FILE_DIR as '/opt/oracle/utl_file'; Directory created. SQL> declare 2 fhandle utl_file.file_type; 3 begin 4 fhandle := utl_file.fopen('UTL_FILE_DIR', 'example.txt', 'w'); 5 utl_file.put_line(fhandle , 'eygle test write one'); 6 utl_file.put_line(fhandle , 'eygle test write two'); 7 utl_file.fclose(fhandle); 8 end; 9 / PL/SQL procedure successfully completed. SQL> ! [oracle@jumper 9.2.0]$ more /opt/oracle/utl_file/example.txt eygle test write one eygle test write two [oracle@jumper 9.2.0]$

类似的我们可以通过utl_file来读取文件:

SQL> declare 2 fhandle utl_file.file_type; 3 fp_buffer varchar2(4000); 4 begin 5 fhandle := utl_file.fopen ('UTL_FILE_DIR','example.txt', 'R'); 6 7 utl_file.get_line (fhandle , fp_buffer ); 8 dbms_output.put_line(fp_buffer ); 9 utl_file.get_line (fhandle , fp_buffer ); 10 dbms_output.put_line(fp_buffer ); 11 utl_file.fclose(fhandle); 12 end; 13 / eygle test write one eygle test write two PL/SQL procedure successfully completed.

可以查询dba_directories查看所有directory.

SQL> select * from dba_directories; OWNER DIRECTORY_NAME DIRECTORY_PATH ------------------------------ ------------------------------ ------------------------------ SYS UTL_FILE_DIR /opt/oracle/utl_file SYS BDUMP_DIR /opt/oracle/admin/conner/bdump SYS EXP_DIR /opt/oracle/utl_file

可以使用drop directory删除这些路径.

SQL> drop directory exp_dir; Directory dropped SQL> select * from dba_directories; OWNER DIRECTORY_NAME DIRECTORY_PATH ------------------------------ ------------------------------ ------------------------------ SYS UTL_FILE_DIR /opt/oracle/utl_file SYS BDUMP_DIR /opt/oracle/admin/conner/bdump

 

(3)、如何查询可用的目录?

可以使用如下SQL查询具有READWRITE权限的目录:

SET lines 80 
COL grantee FORMAT a20 
COL privilege FORMAT a10 
SELECT directory_name, grantee, privilege 
  FROM user_tab_privs t, all_directories d   
 WHERE t.table_name(+)=d.directory_name   
 ORDER BY 1,2,3;

posted on 2015-03-11 08:58  TheViolin  阅读(716)  评论(0编辑  收藏  举报