8. leetcode 485. Max Consecutive Ones

Given a binary array, find the maximum number of consecutive 1s in this array.

Example 1:

Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
    The maximum number of consecutive 1s is 3.

Note:

  • The input array will only contain 0 and 1.
  • The length of input array is a positive integer and will not exceed 10,000

思路:count存储当前连续1的数量,max为最大连续1的数量,遍历数组,遇见0便取count与max的较大者,遇见1则将count加1。要注意最后末尾的1。

 

posted @ 2017-04-09 21:25  蓦然闻声  阅读(129)  评论(0编辑  收藏  举报