sql语句优化小结

sql的优化技巧。

1.用join进行子查询的优化。

低效的子查询
select a.user_name,a.over,(select over from user2 b where a.user_name=b.user_name) as over2 from user1 a;
使用join优化后的子查询：
select a.user_name,a.over,b.over as over2 from user1 a left join user2 b on a.user_name=b.user_name;

　　2.用join进行聚合函数的优化。

使用join + having优化聚合子查询:
select a.user_name,b.timestr,b.kills from user1 a
join user_kills b on a.id = b.user_id
join user_kills c on c.user_id = b.user_id
group by a.user_name,btimestr,b.kills
having b.kills = max(c.kills);

　　3.分类聚合函数的优化

分类聚合方式查询每一个用户某一个字段数据最大的两条数据：
select d.user_name ,c.ctimestr,kills from
(select user_id ,timestr ,kills ,(
select count(*) from user_kills b where b.user_id = a.user_id and a.kills <= b.kills) as cnt 
from user_kills a group by user_id,timestr,kills) c 
join user1 d on c.user_id = d.id where cnt <= 2

    4.自连接行转列

select * from (
select sum(kills) as '孙悟空' from user1 a 
join user_kills b 
on a.id = b.use_id and a.user_name='孙悟空'
) a cross join (
select sum(kills) as '猪八戒' from user1 a 
join user_kills b 
on a.id = b.use_id and a.user_name='猪八戒'
) b cross join(
select sum(kills) as '沙僧' from user1 a 
join user_kills b 
on a.id = b.use_id and a.user_name='沙僧'
) c

　　 5.case语句列转行

select 
sum(case when user_name=' 孙悟空' then kills end) as '孙悟空',
sum(case when user_name='猪八戒' then kills end) as '猪八戒',
sum(case when user_name='沙僧' then kills end) as '沙僧' 
from user1 a join use_kills b 
on a.id = b.user_id;

     6.使用序列化方法转换：

select user_name,
replace(substring(substring_index(mobile,','a.id),char_length(substring_index(mobile,',',a.id-1))+1),',','') as mobile --截取字符串
from tb_sequence as a
cross join(
select user_name,
concat(mobile,',') as mobile, --在mobile结尾增加逗号
length(mobile)-length(replace(mobile,',',''))+1 as size --通过mobile总长度-排除逗号后的长度+1计算得出总段数
from user1 as b 
) as b on a.id<=b.size

   7.使用union all 将结果集 合并

SELECT user_name,'arms' as equipment, arms FROM
user1 a JOIN user1_equipment b ON a.id=b.user_id
UNION ALL
SELECT user_name,'clothing' AS equipment,clothing FROM user1 a JOIN user1_equipment b ON a.id=b.user_id 
UNION ALL
SELECT user_name,'shoe' AS equipment,shoe FROM user1 a JOIN user1_equipment b ON a.id=b.user_id