快速幂 

 1 var
 2   a:array[0..100] of longint;
 3   n,i,j,k:longint;
 4   ans:qword;
 5 begin
 6   readln(n,k);
 7   i:=k;
 8   while i<>0 do begin
 9     inc(a[0]);
10     a[a[0]]:=i and 1;
11     i:=i shr 1;
12   end;ans:=1;
13   for i:=a[0] downto 1 do begin
14     ans:=ans*ans;
15     if a[i]=1 then ans:=ans*n;
16   end;
17   writeln(ans);
18 end.

 

posted @ 2016-02-05 19:44  ZJQCation  阅读(116)  评论(0)  编辑  收藏  举报