scala--定义值--数据类型推导--指定类型与类型推导冲突

C:\Users\Administrator>scala
Welcome to Scala 2.11.12 (Java HotSpot(TM) 64-Bit Server VM, Java 1.8.0_421).
Type in expressions for evaluation. Or try :help.

scala> val x: Int = "Hello";
<console>:11: error: type mismatch;
 found   : String("Hello")
 required: Int
       val x: Int = "Hello";
                    ^

scala>
posted @ 2025-01-22 18:28  基础狗  阅读(4)  评论(0)    收藏  举报