滑动窗口算法-2

给定一个字符串，请你找出其中不含有重复字符的 最长子串 的长度？
输入: "abcabcbb"
输出: 3
解释: 因为无重复字符的最长子串是 "abc"，所以其长度为 3。

public static void main(String[] args) {
        System.out.println(t());
    }


    public static int t() {
        String st = "abcabcbb";
        int startIndex = 0;
        int endIndex = 0;
        int strMaxLen = 0;
        while (endIndex <= st.length() && startIndex <= endIndex) {
            boolean flag = repetitionSubStr(st, startIndex, endIndex);
            System.out.println("===" + flag);
            if (flag) {
                startIndex++;
            }
            if (!flag) {
                strMaxLen = strMaxLen > st.substring(startIndex, endIndex).length() ? strMaxLen : st.substring(startIndex, endIndex).length();
                endIndex++;
            }
        }
        return strMaxLen;
    }

    public static boolean repetitionSubStr(String orgStr, int startIndex, int endIndex) {
        String orgStrTemp = orgStr.substring(startIndex, endIndex);
        System.out.print("orgStrTemp=" + orgStrTemp + "====endIndex=" + endIndex);
        char[] orgStrCharArray = orgStrTemp.toCharArray();
        char[] sub = new char[orgStr.length()];
        for (char s : orgStrCharArray) {
            for (int i = 0; i < sub.length; i++) {
                if (s == sub[i]) {
                    return true;
                }
                if ('\0' == sub[i]) {
                    sub[i] = s;
                    break;
                }
            }
        }
        return false;
    }

算法参考：https://www.zhihu.com/question/314669016