elixir的小作业demo

 #  a =  %{

  #      "mami" => ["a", "d"],

  #      "star" => ["c", "b"]}

  #  b = %{"a" => "1",

  #    "b" => ["2","3","4"],

  #     "c" => ["5","6"],

  #    "d" =>  ["7","8"] }

  #   （思路: 从第一个的a ["a","b","c","d"] 中,遍历取 到b中看是否是b

  #   中的key,若是,则变成map %{}, 插入到a的位置中 ）

  # 变成=>

  #  c =   %{

  #   "mami" => [ %{"a" => "1"}, %{"d" =>  ["7","8"]}],

  #   "star" => [ %{"c" => ["5","6"]}, %{"b" => ["2","3","4"]}]

  #       }

  #       # c =   %{

  #       #   "mami" => [ %{"a" => "1"}],

  #       #   "star" => [ %{"c" => ["5","6"]}]

  #       #       }

  #       #       c1 =   %{

  #       #         "mami" => [ %{"d" =>  ["7","8"]}],

  #       #         "star" => [ %{"b" => ["2","3","4"]}]

  #       #             }

  # cc1 = Enum.map(["c","d"],  fn(x) ->  %{"star" => [%{x => Map.get(b,x)}]} end)

  # Enum.reduce(cc1, %{}, fn m, acc ->

  #   Map.merge(acc, m, fn

  #       _k, v1, v2 when is_list(v1) ->

  #       :lists.reverse([v2 | :lists.reverse(v1)])

  #       _k, v1, v2 -> [v1, v2]

  #   end)

  # end)