hdu1316 java解高精度斐波数
How Many Fibs?
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 3334 Accepted Submission(s): 1340
Problem Description
Recall the definition of the Fibonacci numbers:
f1 := 1
f2 := 2
fn := fn-1 + fn-2 (n >= 3)
Given two numbers a and b, calculate how many Fibonacci numbers are in the range [a, b].
f1 := 1
f2 := 2
fn := fn-1 + fn-2 (n >= 3)
Given two numbers a and b, calculate how many Fibonacci numbers are in the range [a, b].
Input
The input contains several test cases. Each test case consists of two non-negative integer numbers a and b. Input is terminated by a = b = 0. Otherwise, a <= b <= 10^100. The numbers a and b are given with no superfluous leading zeros.
Output
For each test case output on a single line the number of Fibonacci numbers fi with a <= fi <= b.
Sample Input
10 100 1234567890 9876543210 0 0
Sample Output
5 4
import java.math.BigDecimal; import java.math.BigInteger; import java.util.Scanner; public class Main { public static void main(String []args)throws Exception{ Scanner cin = new Scanner(System.in); while(cin.hasNext()){ String a=cin.next(); String b=cin.next(); if(a.equals("0")&&b.equals("0")) break; BigInteger c = new BigInteger(a); BigInteger d = new BigInteger(b); int sum=fibo(c,d); System.out.println(sum); } cin.close(); } public static int fibo(BigInteger a,BigInteger b){ int sum =0; BigInteger f = new BigInteger("1"); BigInteger s = new BigInteger("2"); while(true){ if(f.compareTo(b)>0) break; if(f.compareTo(a)>=0) sum++; BigInteger tem = f; f=s; s=s.add(tem); } return sum; } }