Peter and Snow Blower CodeForces - 613A (点到线段距离)

大意: 给定多边形, 给定点$P$, 求一个以$P$为圆心的最小的圆环包含整个多边形.

 

#include <iostream>
#include <cmath>
#define REP(i,a,b) for(int i=a;i<=b;i++)

const double eps=1e-8;

int dcmp(double x) {return fabs(x)<=eps?0:x>eps?1:-1;}

const int N = 1e5+10;
struct Point {
	double x,y;
	Point(double x=0,double y=0):x(x),y(y) {}
	Point operator + (const Point &a) {return Point(x+a.x,y+a.y);}
	Point operator - (const Point &a) {return Point(a.x-x,a.y-y);}
	Point operator * (double a) {return Point(x*a,y*a);}
	Point operator / (double a) {return Point(x/a,y/a);}
	bool operator < (const Point &b) const {return x<b.x||(x==b.x&&y<b.y);}
	bool operator == (Point b) {return dcmp(x-b.x)==0&&dcmp(y-b.y)==0;}
	double length() {return sqrt(x*x+y*y);}
	Point rotate(double rad) {return Point(x*cos(rad)-y*sin(rad),x*sin(rad)+y*cos(rad));}
	Point normal(Point a) {return Point(-a.y/a.length(),a.x/a.length());}
} a[N];

typedef Point Vector;

double Cross(const Vector& a,const Vector& b) {return a.x*b.y-b.x*a.y;}
double Dot(Vector a,Vector b) {return a.x*b.x+a.y*b.y;}
double Angle(Vector a,Vector b) {return acos(Dot(a,b)/a.length()/b.length());}
double Area(Point a,Point b,Point c) {return Cross(b-a,c-a);}

bool OnSegment(Point p,Point a,Point b) {return dcmp(Cross(a-p,b-p))==0&&dcmp(Dot(a-p,b-p))<0;}
bool Segment_Intersection(Point a1,Point a2,Point b1,Point b2) {return dcmp(Cross(a2-a1,b1-a1))*dcmp(Cross(a2-a1,b2-a1))<0&&dcmp(Cross(b2-b1,a1-b1))*dcmp(Cross(b2-b1,a2-b1))<0;}
Point GetLineIntersection(Point P,Vector v,Point Q,Vector w) {return P+v*(Cross(P-Q,w)/Cross(v,w));}
double DistanceToLine(Point p,Point a,Point b) {Vector v1=b-a,v2=p-a;return fabs(Cross(v1,v2))/v1.length();}
double DistanceToSegment(Point p,Point a,Point b) {
	if(a==b)return (p-a).length();
	Vector v1=b-a,v2=p-a,v3=p-b;
	if(dcmp(Dot(v1,v2))<0)return v2.length();
	else if(dcmp(Dot(v1,v3))>0)return v3.length();
	else return DistanceToLine(p,a,b);
}

double Area(int n,Point* P) {
	double ans=0;
	for(int i=2; i<n; i++)ans+=Area(P[1],P[i],P[i+1]);
	return ans/2;
}

int main() {
	int n,x,y;
	scanf("%d%d%d", &n, &x, &y);
	double mi = 1e18, ma = -1e18;
	REP(i,1,n) {
		int xx, yy;
		scanf("%d%d", &xx, &yy);
		a[i]=Point(xx-x,yy-y);
		ma=max(ma,a[i].length());
	}
	REP(i,2,n) mi=fmin(mi,DistanceToSegment(Point(),a[i],a[i-1]));
	mi=fmin(mi,DistanceToSegment(Point(),a[n],a[1]));
	printf("%.12lf\n",acos(-1)*(ma*ma-mi*mi));
}