2.2阶乘末尾0的个数，最低位1的位置

0的个数

 1 #include <iostream>
 2 using namespace std;
 3 
 4 #include <stdlib.h>
 5 #include <sys/types.h>
 6 
 7 int Count(int n)
 8 {
 9     int count = 0;
10     while (n) {    
11         count += n / 5;
12         n /= 5;
13     }
14     return count;
15 }
16 
17 int main()
18 {
19     cout << Count(26) << endl;
20     
21     return 0;
22 }

1的位置

 1 #include <iostream>
 2 using namespace std;
 3 
 4 #include <stdlib.h>
 5 #include <sys/types.h>
 6 
 7 int Count(int n)
 8 {
 9     int count = 0;
10     while (n) {    
11         count += n / 2;
12         n /= 2;
13     }
14     return count + 1;
15 }
16 
17 int main()
18 {
19     cout << Count(4) << endl;
20     
21     return 0;
22 }

posted on 2011-10-21 14:33 吃吃户阅读(292) 评论(0) 编辑收藏举报