词法分析实验
实验一、词法分析实验
商业软件3班 谭颖欣 244
一、 实验目的
编制一个词法分析程序。通过设计一个编译词法分析程序,实现对词法分析转换的理解,加深对转换过程的认识,通过这个软件把理论知识运用到实际之中。
二、 实验内容和要求
输入:源程序字符串
输出:二元组(种别,单词本身
三、 实验方法、步骤及结果测试
- 1. 源程序名:词法分析_244谭颖欣.c
可执行程序名:词法分析_244谭颖欣.exe
- 2. 原理分析及流程图
#include<stdio.h> #define max 200 int i,n,syn; char pro[max],lin[20]; char *word[6]={"begin","if","then","while","do","end"}; char ch; scaner() { int j=0; for(n=0;n<20;n++) lin[n]=NULL; ch=pro[i++]; while(ch==' ') ch=pro[i++]; if((ch>='A'&&ch<='Z')||(ch>='a'&&ch<='Z')||(ch>=48&&ch<=57)) { if((ch>='A'&&ch<='Z')||(ch>='a'&&ch<='Z')) { lin[j++]=ch; ch=pro[i++]; while((ch>='A'&&ch<='Z')||(ch>='a'&&ch<='Z')||(ch>=48&&ch<=57)) { lin[j++]=ch; ch=pro[i++]; } lin[j]='\0'; i--; syn=10; for(n=0;n<6;n++) if(strcmp(lin,word[n])==0) { syn=n+1; break; } } else { while(ch>=48&&ch<=57) { lin[j++]=ch; ch=pro[i++]; } i--; lin[j]='\0'; syn=11; } } else { if(ch=='<') {lin[j++]=ch; ch=pro[i++]; if (ch=='>') { syn=21; lin[j++]=ch; lin[j]='\0'; } else if(ch=='=') { syn=22; lin[j++]=ch; lin[j]='\0'; } else { syn=20; lin[j]='\0'; i--; } } else if(ch=='>') { lin[j++]=ch; ch=pro[i++]; if (ch=='=') { syn=24; lin[j++]=ch; lin[j]='\0'; } else { syn=23; lin[j]='\0'; i--; } } else if(ch==':') { lin[j++]=ch; ch=pro[i++]; if (ch=='=') { syn=18; lin[j++]=ch; lin[j]='\0';} else { syn=17; lin[j]='\0'; i--; } } else if(ch=='+') {syn=13; lin[j++]=ch; lin[j]='\0'; } else if(ch=='-') { syn=14; lin[j++]=ch; lin[j]='\0';} else if(ch=='*') { syn=15; lin[j++]=ch; lin[j]='\0';} else if(ch=='/') { syn=16; lin[j++]=ch; lin[j]='\0'; } else if(ch=='=') { syn=25; lin[j++]=ch; lin[j]='\0'; } else if(ch==';') { syn=26; lin[j++]=ch; lin[j]='\0'; } else if(ch=='(') { syn=27; lin[j++]=ch; lin[j]='\0'; } else if(ch==')') { syn=28; lin[j++]=ch; lin[j]='\0';} else if(ch=='#') { syn=0; lin[j++]=ch; lin[j]='\0'; } else syn=-1; } return syn; } void main() { int i=0 ; printf("**************************************************************************\n"); printf("*********************************种别编码*********************************\n"); printf("**************************************************************************\n"); printf("(1,begin) (2,if) (3,then) (4,while) (5,do)\n"); printf("(6,end) (10,基本标示符) (11,数字) (13, ) (14,-)\n"); printf("(15,*) (16,/) (17,:) (18,:=) (20,<)\n"); printf("(21,<>) (22,<=) (23,>) (24,>=) (25,=)\n"); printf("(26,;) (27,() (28,)) (0,#)\n"); read(); printf( "读入的字符串如下: \n\n" ); puts(pro); printf( "词法分析结果如下:\n" ); printf( "\n" ); do { scaner(); switch(syn) { case 11: printf ("(%d,%s)\n",syn,lin); break; case -1: printf("错误符号\n"); break; default: printf ("(%d,%s)",syn,lin); } } while (syn!=0); printf( "\n词法分析结束\n" ); scanf("%c",&i);
- 3. 主要程序段及其解释:
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if((ch>='A'&&ch<='Z')||(ch>='a'&&ch<='Z')||(ch>=48&&ch<=57)) { if((ch>='A'&&ch<='Z')||(ch>='a'&&ch<='Z')) { lin[j++]=ch; ch=pro[i++]; while((ch>='A'&&ch<='Z')||(ch>='a'&&ch<='Z')||(ch>=48&&ch<=57)) { lin[j++]=ch; ch=pro[i++]; } lin[j]='\0'; i--; syn=10; for(n=0;n<6;n++) if(strcmp(lin,word[n])==0) { syn=n+1; break; } } else { while(ch>=48&&ch<=57) { lin[j++]=ch; ch=pro[i++]; } i--; lin[j]='\0'; syn=11; } } else { if(ch=='<') {lin[j++]=ch; ch=pro[i++]; if (ch=='>') { syn=21; lin[j++]=ch; lin[j]='\0'; } else if(ch=='=') { syn=22; lin[j++]=ch; lin[j]='\0'; } else { syn=20; lin[j]='\0'; i--; } } else if(ch=='>') { lin[j++]=ch; ch=pro[i++]; if (ch=='=') { syn=24; lin[j++]=ch; lin[j]='\0'; } else { syn=23; lin[j]='\0'; i--; } } else if(ch==':') { lin[j++]=ch; ch=pro[i++]; if (ch=='=') { syn=18; lin[j++]=ch; lin[j]='\0';} else { syn=17; lin[j]='\0'; i--; } } else if(ch=='+') {syn=13; lin[j++]=ch; lin[j]='\0'; } else if(ch=='-') { syn=14; lin[j++]=ch; lin[j]='\0';} else if(ch=='*') { syn=15; lin[j++]=ch; lin[j]='\0';} else if(ch=='/') { syn=16; lin[j++]=ch; lin[j]='\0'; } else if(ch=='=') { syn=25; lin[j++]=ch; lin[j]='\0'; } else if(ch==';') { syn=26; lin[j++]=ch; lin[j]='\0'; } else if(ch=='(') { syn=27; lin[j++]=ch; lin[j]='\0'; } else if(ch==')') { syn=28; lin[j++]=ch; lin[j]='\0';} else if(ch=='#') { syn=0; lin[j++]=ch; lin[j]='\0'; } else syn=-1; } return syn; }
- 判断词的种类
- . 运行结果及分析
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四、 实验总结
对于词法分析的输入,有些不懂。通过用字符数组的方式储存来解决。