c# JArray提取JSON格式数组获取指定字段元素数据
Newtonsoft.Json.dll
if (retString.Contains("boxid")) { dynamic jsonStr = JsonConvert.DeserializeObject<dynamic>(retString); // jsonStr["data"]["lblList"][0]["lblno"] = $"{where_name}"; JArray array2 = jsonStr["data"]["lblList"]; // string output = JsonConvert.SerializeObject(jsonStr2, Newtonsoft.Json.Formatting.Indented); // JArray array = (JArray)JsonConvert.DeserializeObject(output); dynamic jsonStr2 = array2[0]; //string output = JsonConvert.SerializeObject(jsonStr2, Newtonsoft.Json.Formatting.Indented); string aa = jsonStr2["lblno"]; }
retString原始数据
{ "code": 1, "data": { "lblList": [ { "boxid": "10180129LES8553567", "creator": "AG2952", "ctime": "2018-01-29 14:28:39", "id": "39805809", "iscopy": null, "layer": "0", "lblno": "1898622", "lot": "SLA18036148", "packruleid": "PR-007", "ptimes": null, "qty": "10000", "rpoper": null, "rptime": null, "seqno": "002" }, { "boxid": "10180129LES8553570", "creator": "AG2952", "ctime": "2018-01-29 14:28:39", "id": "39805812", "iscopy": null, "layer": "0", "lblno": "1898625", "lot": "SLA18036148", "packruleid": "PR-007", "ptimes": null, "qty": "10000", "rpoper": null, "rptime": null, "seqno": "005" }, { "boxid": "20180129LES8553566", "creator": "AG2952", "ctime": "2018-01-29 14:28:39", "id": "40052739", "iscopy": null, "layer": "0", "lblno": "1898621", "lot": "SLA18036148", "packruleid": "PR-007", "ptimes": null, "qty": "10000", "rpoper": null, "rptime": null, "seqno": "001" } ], "lotId": "SLA18036148" }, "message": "成功" }
欢迎讨论,相互学习。
cdtxw@foxmail.com
分类:
C#
【推荐】国内首个AI IDE,深度理解中文开发场景,立即下载体验Trae
【推荐】编程新体验,更懂你的AI,立即体验豆包MarsCode编程助手
【推荐】抖音旗下AI助手豆包,你的智能百科全书,全免费不限次数
【推荐】轻量又高性能的 SSH 工具 IShell:AI 加持,快人一步
· 震惊!C++程序真的从main开始吗?99%的程序员都答错了
· 别再用vector<bool>了!Google高级工程师:这可能是STL最大的设计失误
· 单元测试从入门到精通
· 【硬核科普】Trae如何「偷看」你的代码?零基础破解AI编程运行原理
· 上周热点回顾(3.3-3.9)