【POJ1208】The Blocks Problem

来源:The Blocks Problem

推导:(略)

设计:

  f(i): 把叠在木块i上的其他木块放回初始位置.

  m(i,j): 把i及其以上的木块全叠到包含j的上方.

  move a onto b => f(a),f(b),m(a,b)

  move a over b => f(a),m(a,b)

  pile a onto b   => f(b),m(a,b)

  pile a over b  => m(a,b)

代码:

#include <iostream>
using namespace std;

#define N 24

//
struct Node{
int No; //编号
struct Node *next;
};

struct Node *station[N];//原始的块位置
int place[N];//当前各块所在的位置

struct Node *Find(int i,bool setNULL)
{
struct Node *p,*q;
int j = place[i];
if(station[j]->No == i)
{
p
=station[j];
if(setNULL)
station[j]
= NULL;
return p;
}
else
{
q
=station[j];
p
=q->next;
while(p->No!=i)
{
q
=p;
p
=q->next;
}
if(setNULL)
q
->next=NULL;
return p;
}
}

void F(int i)
{
struct Node *p;
p
=Find(i,false);

if(p->next==NULL)
return;

int j;
while(p->next!=NULL)
{
j
= p->next->No;
station[j]
= p->next;
place[j]
= j;
p
->next=NULL;
p
=station[j];
}
}

void M(int i,int j)
{
if( i==j || place[i]==place[j] )
return;

struct Node *p,*q;
p
=Find(i,true);
q
=Find(j,false);

while(q->next!=NULL)
q
=q->next;

q
->next = p;

while(p!=NULL)
{
place[p
->No]=place[q->No];
p
=p->next;
}

}

void MoveAOntoB(int i,int j)
{
F(i);
F(j);
M(i,j);
}

void MoveAOverB(int i,int j)
{
F(i);
M(i,j);
}

void PileAOntoB(int i,int j)
{
F(j);
M(i,j);
}

void PileAOverB(int i,int j)
{
M(i,j);
}

void Init()
{
for( int i=0;i<N;i++ )
{
place[i]
= i;
station[i]
= (struct Node *)malloc(sizeof(struct Node));
station[i]
->No = i;
station[i]
->next = NULL;
}

}

int main()
{
int n;
char ch1[5],ch2[5];
int a,b;
struct Node *p;
cin
>> n;
Init();
while(cin >> ch1 && strcmp(ch1,"quit")!=0 )
{
cin
>> a;
cin
>> ch2;
cin
>> b;
if( strcmp(ch1,"move")==0 )
{
if( strcmp(ch2,"onto")==0 )
MoveAOntoB(a,b);
else
MoveAOverB(a,b);
}
else
{
if( strcmp(ch2,"onto")==0 )
PileAOntoB(a,b);
else
PileAOverB(a,b);
}
}

for( int i=0;i<n;i++ )
{
cout
<<i<<": ";
p
= station[i];
while(p!=NULL)
{
cout
<<p->No<<" ";
p
=p->next;
}
cout
<< endl;
}

return 1;
}

 

 

 

posted @ 2010-09-27 11:15  屠一刀  阅读(395)  评论(0编辑  收藏  举报