scrapy

scrapy extract提取出的是list,且selectors返回list.

 

创建项目:scrapy startproject myproject

下载内容并送到标准输出:

scrapy fetch --nolog http://www.example.com/some/page.html

scrapy fetch --nolog --headers http://www.example.com/

用浏览器打开指定的URL

scrapy view <url>

启动shell

scrapy shell [url]

使用spider分给定url

scrapy parse http://www.example.com/ -c parse_item

在运行crawl时添加-a可以传递spider参数

scrapy crawl myspider -a category=electronics

import scrapy

class MySpider(Spider):
    name = 'myspider'

    def __init__(self, category=None, *args, **kwargs):
        super(MySpider, self).__init__(*args, **kwargs)
        self.start_urls = ['http://www.example.com/categories/%s' % category]

  

rules = (
        # 提取匹配 'category.php' (但不匹配 'subsection.php') 的链接并跟进链接(没有callback意味着follow默认为True)
        Rule(LinkExtractor(allow=('category\.php', ), deny=('subsection\.php', ))),

        # 提取匹配 'item.php' 的链接并使用spider的parse_item方法进行分析
        Rule(LinkExtractor(allow=('item\.php', )), callback='parse_item'),
    )

  

>>> response.xpath('//title/text()')
[<Selector (text) xpath=//title/text()>]
>>> response.css('title::text')
[<Selector (text) xpath=//title/text()>]

  

>>> links = response.xpath('//a[contains(@href, "image")]')
>>> links.extract()
[u'<a href="image1.html">Name: My image 1 <br><img src="image1_thumb.jpg"></a>',
 u'<a href="image2.html">Name: My image 2 <br><img src="image2_thumb.jpg"></a>',
 u'<a href="image3.html">Name: My image 3 <br><img src="image3_thumb.jpg"></a>',
 u'<a href="image4.html">Name: My image 4 <br><img src="image4_thumb.jpg"></a>',
 u'<a href="image5.html">Name: My image 5 <br><img src="image5_thumb.jpg"></a>']

>>> for index, link in enumerate(links):
        args = (index, link.xpath('@href').extract(), link.xpath('img/@src').extract())
        print 'Link number %d points to url %s and image %s' % args

Link number 0 points to url [u'image1.html'] and image [u'image1_thumb.jpg']
Link number 1 points to url [u'image2.html'] and image [u'image2_thumb.jpg']
Link number 2 points to url [u'image3.html'] and image [u'image3_thumb.jpg']
Link number 3 points to url [u'image4.html'] and image [u'image4_thumb.jpg']
Link number 4 points to url [u'image5.html'] and image [u'image5_thumb.jpg']

  

>>> response.xpath('//a[contains(@href, "image")]/text()').re(r'Name:\s*(.*)')
[u'My image 1',
 u'My image 2',
 u'My image 3',
 u'My image 4',
 u'My image 5']

divs = response.xpath('//div')

提取出divs后应该用for p in divs.xpath('.//p')而不是for p in divs.xpath('//p'),起始为 / 的XPath,那么该XPath将对文档使用绝对路径.

如果p是直系亲属的话用divs.xpath('p').

>>> from scrapy import Selector
>>> doc = """
... <div>
...     <ul>
...         <li class="item-0"><a href="link1.html">first item</a></li>
...         <li class="item-1"><a href="link2.html">second item</a></li>
...         <li class="item-inactive"><a href="link3.html">third item</a></li>
...         <li class="item-1"><a href="link4.html">fourth item</a></li>
...         <li class="item-0"><a href="link5.html">fifth item</a></li>
...     </ul>
... </div>
... """
>>> sel = Selector(text=doc, type="html")
>>> sel.xpath('//li//@href').extract()
[u'link1.html', u'link2.html', u'link3.html', u'link4.html', u'link5.html']
>>> sel.xpath('//li[re:test(@class, "item-\d$")]//@href').extract()
[u'link1.html', u'link2.html', u'link4.html', u'link5.html']
>>>
for scope in sel.xpath('//div[@itemscope]'):
...     print "current scope:", scope.xpath('@itemtype').extract()
...     props = scope.xpath('''
...                 set:difference(./descendant::*/@itemprop,
...                                .//*[@itemscope]/*/@itemprop)''')
...     print "    properties:", props.extract()
...     print

  

posted on 2015-01-04 11:33  颓废的悠然  阅读(523)  评论(0编辑  收藏  举报

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