reverse

url中用法:

urlpatterns = patterns(’’,
url(r’^archive/(\d{4})/$’, archive, name="full-archive"),
url(r’^archive-summary/(\d{4})/$’, archive, {’summary’: True}, name="arch-summary"),
)

函数中用法:

year = 2006
return HttpResponseRedirect(reverse(’full-archive’, args=(year,)))

模板中用法:

{% url ’arch-summary’ 1945 %}
{% url ’full-archive’ 2007 %}

posted on 2014-07-21 11:17  颓废的悠然  阅读(202)  评论(0编辑  收藏  举报

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