摘要: String a="ASD1232@#"; //System.out.println(HasDigit(a)); //gettime(); //【含有英文】true String regex1 = ".*[a-zA-z].*"; boolean result3 = a.matches(regex1) 阅读全文
posted @ 2020-11-17 11:12 哎呀呀呀呀~~ 阅读(2900) 评论(0) 推荐(1) 编辑
摘要: String ul="00009"; int utellength=ul.length(); String u=""; for (int i = 0; i < utellength; i++) { u=u+"0"; } System.out.println("u:"+u); BigInteger u 阅读全文
posted @ 2020-11-17 11:09 哎呀呀呀呀~~ 阅读(1612) 评论(0) 推荐(0) 编辑