代码改变世界

几道编程题

2012-09-16 01:23  coodoing  阅读(567)  评论(0编辑  收藏  举报

直接上代码

试题1:

   1: public class Test1 {
   2:  
   3:     static void convert(String str) {
   4:         int count = 1; // 用于记录当前连续字符的数量
   5:         char[] input = str.toCharArray();
   6:         char pre = '\u0000', cur; // char为空判断
   7:         char output;
   8:         
   9:         for (char ele : input) {
  10:             cur = ele;
  11:             if (cur == pre) {
  12:                 count++;
  13:                 // 连续两个字符
  14:                 if (count == 2) {
  15:                     
  16:                     output = (char) traverse(cur,cur + 2);
  17:                     System.out.print(output);
  18:                 }
  19:                 // 连续三个及以上字符
  20:                 if (count >= 3) {
  21:                     output = (char) traverse(cur,cur + count - 2);
  22:                     System.out.print(output);
  23:                 }
  24:             } else {
  25:                 count = 1;
  26:                 pre = cur; // 赋值
  27:                 
  28:                 output = (char) traverse(cur,ele + 1);//traverse
  29:                 System.out.print(output);
  30:             }
  31:  
  32:         }
  33:         System.out.println();
  34:     }
  35:     
  36:     static int traverse(char ch,int num)
  37:     {
  38:         boolean upper = false;
  39:         if(Character.isUpperCase(ch))
  40:         {
  41:             upper = true;
  42:         }
  43:         // 越界z
  44:         if(upper==false&&num>122)
  45:         {            
  46:             num = (num-97)%26+97;//num = (char)(num-26);
  47:             //System.out.println(num);
  48:         }
  49:         // 越界Z
  50:         if(upper&&num >90)
  51:         {
  52:             num = (num-65)%26+65;//num = (char)(num-26);
  53:         }
  54:         return num;
  55:     }
  56:     
  57:     /**
  58:      * @param args
  59:      */
  60:     public static void main(String[] args) {
  61:         // TODO Auto-generated method stub
  62:         String input1 = "abcd";
  63:         String input2 = "abbcd";// "abb";
  64:         String input3 = "abbbcd";
  65:         String input4 = "abbbbbcccd";
  66:         String input5 = "abzzcdeeeg";
  67:  
  68:         convert(input1);
  69:         convert(input2);
  70:         convert(input3);
  71:         convert(input4);
  72:         convert(input5);
  73:         
  74:         System.out.println((char)67);
  75:         System.out.println('a' > 96);
  76:     }
  77: }

试题2:

   1: import java.util.ArrayList;
   2: import java.util.Collections;
   3: import java.util.Comparator;
   4: import java.util.HashMap;
   5: import java.util.List;
   6: import java.util.Map;
   7: import java.util.Map.Entry;
   8:  
   9: public class Test2 {
  10:  
  11:     static void sort(String str) {
  12:         char[] input = str.toCharArray();
  13:         
  14:         /* 字符串替换思路
  15:          * char[] replace = new char[input.length];
  16:         for (int i = 0; i < input.length; i++) {
  17:             // 这里可以用正则进行通配符的匹配
  18:             if (input[i] == ',' || (input[i] > '1' && input[i] < '9')) {
  19:                 replace[i] = ' '; //数据替换
  20:             } else
  21:                 replace[i] = input[i];
  22:             //System.out.print(replace[i]);
  23:         }
  24:         String rep = String.valueOf(replace); //数据处理后的字符串
  25:         System.out.println(rep);
  26:         String[] array = rep.split(" "); //这里没有对string合法做验证
  27: 
  28:         HashMap<String, Integer> map = new HashMap<String, Integer>();
  29:         for (String s : array) {
  30:             if (s != "" && !s.equals("")) {
  31:                 map.put(s, s.length());
  32:             }
  33:         }*/
  34:         
  35:         HashMap<String, Integer> map = new HashMap<String, Integer>();        
  36:         StringBuffer temp = new StringBuffer();
  37:         for(int i=0;i<input.length;i++)
  38:         {
  39:             // 小写大写字母
  40:             if((input[i]>96&&input[i]<123)||(input[i]>64&&input[i]<91))
  41:             {
  42:                 temp.append(input[i]);
  43:             }
  44:             // 即单词已经找到
  45:             else if(temp.length()>1)
  46:             {                
  47:                 map.put(temp.toString(), temp.length());
  48:                 temp = new StringBuffer();// 置空处理
  49:             }
  50:         }
  51:  
  52:         List<Map.Entry<String, Integer>> list = new ArrayList<Map.Entry<String, Integer>>(
  53:                 map.entrySet());
  54:  
  55:         //根据字符串长度进行排序
  56:         Collections.sort(list, new Comparator<Map.Entry<String, Integer>>() {
  57:             public int compare(Map.Entry<String, Integer> o1,
  58:                     Map.Entry<String, Integer> o2) {
  59:                 return (o2.getValue() - o1.getValue());
  60:                 //return (o1.getKey()).toString().compareTo(o2.getKey());
  61:             }
  62:         });
  63:  
  64:         for (int i = 0; i < list.size(); i++) {
  65:             String id = list.get(i).toString();
  66:             System.out.print(id + " ");
  67:         }
  68:         System.out.println();
  69:  
  70:         for (Entry<String, Integer> e : list) {
  71:             if (e.getValue() != 1)
  72:                 System.out.print(e.getKey() + " ");
  73:         }
  74:  
  75:     }
  76:  
  77:     /**
  78:      * @param args
  79:      */
  80:     public static void main(String[] args) {
  81:         // TODO Auto-generated method stub
  82:  
  83:         String str1 = "some drivers drink when the d234drives";
  84:         sort(str1);
  85:     }
  86: }

试题3:

   1: public class Test3 {
   2:  // 适合int范围内数
   3:     static String minus(String s1, String s2) {
   4:         char[] str1 = s1.toCharArray();
   5:         char[] str2 = s2.toCharArray();
   6:  
   7:         int forward_number1 = 0, forward_number2 = 0; // 两个数的整数部分
   8:         int backward_number1 = 0, backward_number2 = 0; // 两个数的小数部分对应的整数
   9:  
  10:         int len1 = str1.length, len2 = str2.length;
  11:         int pos1 = -1, pos2 = -1;
  12:  
  13:         double number1, number2;
  14:  
  15:         if (s1.indexOf('.') != -1) {
  16:             pos1 = s1.indexOf('.');
  17:             pos2 = s2.indexOf('.');
  18:         }
  19:  
  20:         for (int i = 0; i < str1.length; i++) {
  21:             if (pos1 != -1 && i < pos1) {
  22:                 forward_number1 = forward_number1 * 10 + (str1[i] - '0');
  23:             } else if (i > pos1)
  24:                 backward_number1 = backward_number1 * 10 + (str1[i] - '0');
  25:         }
  26:         // System.out.println(forward_number1 + " " + backward_number1);
  27:  
  28:         for (int i = 0; i < str2.length; i++) {
  29:             if (pos2 != -1 && i < pos2) {
  30:                 forward_number2 = forward_number2 * 10 + (str2[i] - '0');
  31:             } else if (i > pos2) {
  32:                 backward_number2 = backward_number2 * 10 + (str2[i] - '0');
  33:             }
  34:         }
  35:         // System.out.println(forward_number2 + " " + backward_number2);
  36:  
  37:         // 更简单的处理方法是:直接将小数转换为整数
  38:         int mul = (len1 - pos1) > (len2 - pos2) ? (len1 - pos1 - 1) : (len2
  39:                 - pos2 - 1);
  40:  
  41:         number1 = forward_number1 * Math.pow(10, mul) + backward_number1;
  42:         number2 = forward_number2 * Math.pow(10, mul) + backward_number2;
  43:         // System.out.println(number1 + " " + number2);
  44:  
  45:         double result = (number1 - number2) / Math.pow(10, mul);
  46:         // System.out.println(result);
  47:  
  48:         return String.valueOf(result);
  49:     }
  50:  
  51:     /**
  52:      * @param args
  53:      */
  54:     public static void main(String[] args) {
  55:         // TODO Auto-generated method stub
  56:  
  57:         String s11 = "1.1";
  58:         String s12 = "2.2";
  59:  
  60:         String s21 = "2.2";
  61:         String s22 = "1.1";
  62:  
  63:         String s31 = "10.1";
  64:         String s32 = "9.23";
  65:  
  66:         System.out.println(minus(s12, s11));
  67:         System.out.println(minus(s22, s21));
  68:         System.out.println(minus(s32, s31));
  69:     }
  70:  
  71: }